d (4, 3, -2, -1/2) →→ Negatnes amol go in front For each element on the periodic table, we can use this diagram to describe the electrons and where (what energy levels/atomic orbitals) they are likely to be found when in the ground state. 5. For carbon (C) draw a new diagram with the correct number of electrons. Fill in the lowest energy levels first and "build up" from there.

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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(4, 3, -2, –1/2) Negatnes amayi go in
rant
For each element on the periodic table, we can use this diagram to describe the electrons and where (what
energy levels/atomic orbitals) they are likely to be found when in the ground state.
5. For carbon (C) draw a new diagram with the correct number of electrons. Fill in the lowest energy levels
first and "build up" from there.
This orbital diagram can then be translated into an electron configuration, which is a short-hand notation
describing where the electrons are found. For example; hydrogen has 1 eleciron in n= 1,1 = 0 and its electron
configuration is H: 1s'. Helium has 2 electrons in n= 1, 1= 0 and its electron configuration is He: 1s.
6. Write the electron configuration for carbon (C) using the orbital diagram you completed in the previous
problem.
7. Now try writing an electron configuration for fluorine (F). You may want to draw the diagram first but
don't have to.
Transcribed Image Text:(4, 3, -2, –1/2) Negatnes amayi go in rant For each element on the periodic table, we can use this diagram to describe the electrons and where (what energy levels/atomic orbitals) they are likely to be found when in the ground state. 5. For carbon (C) draw a new diagram with the correct number of electrons. Fill in the lowest energy levels first and "build up" from there. This orbital diagram can then be translated into an electron configuration, which is a short-hand notation describing where the electrons are found. For example; hydrogen has 1 eleciron in n= 1,1 = 0 and its electron configuration is H: 1s'. Helium has 2 electrons in n= 1, 1= 0 and its electron configuration is He: 1s. 6. Write the electron configuration for carbon (C) using the orbital diagram you completed in the previous problem. 7. Now try writing an electron configuration for fluorine (F). You may want to draw the diagram first but don't have to.
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