(D² – 3D – 4)y = 0 is ° y = C,e** + C,e* " y = C,e** + C,e* 4х 4x -X -4x ° y = C,e** + C,e* y = C,e* + C,e* -x -4x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution of 

(D² – 3D – 4)y = 0
is
° y = C,e** + C,e*
" y = C,e** + C,e*
4х
4x
-X
-4x
° y = C,e** + C,e*
y = C,e* + C,e*
-x
-4x
Transcribed Image Text:(D² – 3D – 4)y = 0 is ° y = C,e** + C,e* " y = C,e** + C,e* 4х 4x -X -4x ° y = C,e** + C,e* y = C,e* + C,e* -x -4x
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