D \36 ст B 4 x +8

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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### Educational Website Content: Solving for \( x \) in a Tangent-Secant Circle Problem

**Problem Overview:**

We are given a geometric figure involving a circle with center \( C \). In the figure:

- \( AB \) is a secant line that intersects the circle at points \( B \) and \( D \).
- \( AD \) is a tangent to the circle at point \( D \).
- \( AB = 4x + 8 \) cm.
- \( AD = 36 \) cm.

Our goal is to solve for \( x \).

**Diagram Explanation:**

- The circle is depicted with center \( C \).
- Point \( B \) lies on the circle, making \( AB \) a secant, while point \( D \) lies on the circle where the tangent \( AD \) touches it.
- \( B \) and \( D \) are points where the line segments intersect the circle, and point \( A \) is external to the circle.
- \( AD \) (tangent) and \( AB \) (secant) create a specific relationship: the power of a point theorem (sometimes referred to as the Tangent-Secant Theorem) can be applied here.

**Using the Tangent-Secant Theorem:**

The Tangent-Secant Theorem states that:
\[ AD^2 = AB \cdot AB_{ext} \]
Where:
- \( AD \) is the length of the tangent from \( A \) to the point of tangency \( D \).
- \( AB \) is the length of the full secant segment from \( A \) through \( B \) to the circle.
- \( AB_{ext} \) is the exterior part of the secant segment from \( A \) to \( B \) (which is the same as \( AB \)).

Given:
- \( AD = 36 \) cm,
- \( AB = 4x + 8 \),

Applying the theorem:
\[ AD^2 = AB \cdot AB_{ext} \]
\[ 36^2 = (4x + 8) \cdot (4x + 8) \]
\[ 1296 = (4x + 8)^2 \]

Solve for \( x \):
1. Expand the right side:
\[ 1296 = 16x^2 + 64x
Transcribed Image Text:### Educational Website Content: Solving for \( x \) in a Tangent-Secant Circle Problem **Problem Overview:** We are given a geometric figure involving a circle with center \( C \). In the figure: - \( AB \) is a secant line that intersects the circle at points \( B \) and \( D \). - \( AD \) is a tangent to the circle at point \( D \). - \( AB = 4x + 8 \) cm. - \( AD = 36 \) cm. Our goal is to solve for \( x \). **Diagram Explanation:** - The circle is depicted with center \( C \). - Point \( B \) lies on the circle, making \( AB \) a secant, while point \( D \) lies on the circle where the tangent \( AD \) touches it. - \( B \) and \( D \) are points where the line segments intersect the circle, and point \( A \) is external to the circle. - \( AD \) (tangent) and \( AB \) (secant) create a specific relationship: the power of a point theorem (sometimes referred to as the Tangent-Secant Theorem) can be applied here. **Using the Tangent-Secant Theorem:** The Tangent-Secant Theorem states that: \[ AD^2 = AB \cdot AB_{ext} \] Where: - \( AD \) is the length of the tangent from \( A \) to the point of tangency \( D \). - \( AB \) is the length of the full secant segment from \( A \) through \( B \) to the circle. - \( AB_{ext} \) is the exterior part of the secant segment from \( A \) to \( B \) (which is the same as \( AB \)). Given: - \( AD = 36 \) cm, - \( AB = 4x + 8 \), Applying the theorem: \[ AD^2 = AB \cdot AB_{ext} \] \[ 36^2 = (4x + 8) \cdot (4x + 8) \] \[ 1296 = (4x + 8)^2 \] Solve for \( x \): 1. Expand the right side: \[ 1296 = 16x^2 + 64x
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