D 3 m 2 m A 4 m B = F(AB)=tension force in AB FAB E АВ F = F(AD)=tension force in AD %3D AD F = F(AC)=tension force in AC AC Weight of the flowerpot is 40 Newton. W=weight of the flowerpot Express the tension force in AD as a vector form.
D 3 m 2 m A 4 m B = F(AB)=tension force in AB FAB E АВ F = F(AD)=tension force in AD %3D AD F = F(AC)=tension force in AC AC Weight of the flowerpot is 40 Newton. W=weight of the flowerpot Express the tension force in AD as a vector form.
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Transcribed Image Text:D
3 m
y
2 m
4 m
В
E
FAB- F(AB)=tension force in AB
F
= F(AD)=tension force in AD
%3D
AD
F = F(AC)=tension force in AC
AC
Weight of the flowerpot is 40 Newton.
W=weight of the flowerpot
Express the tension force in AD as a vector form.
![O A) F(AD)*[(-0.5714) i+ (-0.0428) j+(0.4571) k] N
O B) F(AD)*[(-0,3714) i+ (-0.5428) j]N
O O F(AD)*[(-0.3714) i+ (-0.7428) j+ (0.5571) k] N
O D) F(AD)*[(-0.7428) j+ (0.5571) k] N
O E) F(AD)*[(-0.1714) i+ (0.3428) j- (0.3714) k] N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2496ad30-da96-46fb-a0a6-b9c875e5f38b%2F15a20adc-bf68-4885-925b-c14607606e76%2Fnr7cmvg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:O A) F(AD)*[(-0.5714) i+ (-0.0428) j+(0.4571) k] N
O B) F(AD)*[(-0,3714) i+ (-0.5428) j]N
O O F(AD)*[(-0.3714) i+ (-0.7428) j+ (0.5571) k] N
O D) F(AD)*[(-0.7428) j+ (0.5571) k] N
O E) F(AD)*[(-0.1714) i+ (0.3428) j- (0.3714) k] N
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