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D= 3 in L= 250 ft D= 2 in L= 200 ft

D= 3 in L= 250 ft D= 2 in L= 200 ft

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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If the two pipes in Fig.  are instead laid in series
with the same total pressure drop of 3 lbf/in2, what will the
flow rate be? The fluid is SAE 10 oil at 20°C.

D= 3 in L= 250 ft D= 2 in L= 200 ft
Transcribed Image Text:D= 3 in L= 250 ft D= 2 in L= 200 ft
Expert Solution
Step 1

Given data:

  • The pressure drop is, ∆P = 3 lbf/in2.

Calculate the flow rate as follows:

ΔP=128μQπL1D14+L2D24

Here, Q is the flow rate, μ is the dynamic viscosity, L1 is the length of tube 1, L2 is the length of tube 2, D1 is the diameter of tube 1, and D2 is the diameter of tube 2.

Refer the table “properties of sae 10” to obtain the viscosity.

μ = 0.00217 slug/ftˑs

 

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