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Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐

Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐<p<0
Transcribed Image Text:Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐<p<0
decimal places. Round your final answers to at least three decimal places. Explanation Formula for a Specific Confidence Interval for a Proportion A P-²a/2 · <p<p +²α/²\/ pa pq n n when n p and nq are each greater than or equal to 5. Since a 1-0.9=0.1, ²a/2 = 1.65. Find p and q. p = 0.32 q=1-p=1-0.32 = 0.68 Calculate the confidence interval. 7-2222-²2-124 pq pa P-²a/2 <p<p +²a/2 n n (0.32) (0.68) (0.32) (0.68) 0.32 1.65 <p<0.32+ 1.65 900 900 0.32 0.02566<p<0.32+0.02566 0.294<p<0.346 Hence, we can be 90% confident that the proportion of U.S. adults who would not get work done on Cyber Monday is between 0.294 and 0.346, based on a sample of 900 adults.
Transcribed Image Text:decimal places. Round your final answers to at least three decimal places. Explanation Formula for a Specific Confidence Interval for a Proportion A P-²a/2 · <p<p +²α/²\/ pa pq n n when n p and nq are each greater than or equal to 5. Since a 1-0.9=0.1, ²a/2 = 1.65. Find p and q. p = 0.32 q=1-p=1-0.32 = 0.68 Calculate the confidence interval. 7-2222-²2-124 pq pa P-²a/2 <p<p +²a/2 n n (0.32) (0.68) (0.32) (0.68) 0.32 1.65 <p<0.32+ 1.65 900 900 0.32 0.02566<p<0.32+0.02566 0.294<p<0.346 Hence, we can be 90% confident that the proportion of U.S. adults who would not get work done on Cyber Monday is between 0.294 and 0.346, based on a sample of 900 adults.
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