Customers of a beauty salon were surveyed to see which type of service they had during their visit (hair, nails, or skin) and their age (18 years or younger or over 18 years old). The results of the survey weredisplayed in a joint relative frequency table.Which of the following describes this data set?O Numerical and univariateO Numerical and bivariateO Categorical and univariateO Categorical and bivariate

Given: Variables: Type of service Age

Answered: Customers of a beauty salon were…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Insurance componies track life expertancy info to assist in determining the cost of life insurance polocies. The insurance compony knows that last year the life expectancy of its polocy holders was 77 years. They want to know if their clients this year have a longer life expectancy, on average, so the company randomy samples some of the recently paid polices to see if the mean life expectancy of polcy holders has increased. Sample: 86,75, 83, 84, 81, 77, 78, 79, 79,81, 76, 85, 70,76, 79,81, 73, 74, 72, 83. 1) Does this sample indicate that the insurance company should change its premiums because life expectancy has increased? 2) For more accurate cost determination, the insurance companies want to estimate the life expectancy to within one year with 95% confidence. How many randomly selected records would you need to have?
Which statistical analysis is needed to address this research question: H2: Men and women will differ in how rewarding they find their relationships. One sample t-test Two sample t-test ANOVA Paired sample t-test
The midterm and final exam grades for a statistics course are provided in the data set below. Jaymes, a student in the class, scored 86 on both exams. Treat the given data sets as samples. Midterm: 80, 78, 85, 82, 79, 79, 78, 86, 80, 84, 78, 84, 80, 84, 81, 78, 81, 82, 78, 84 Final: 81, 88, 68, 69, 69 81, 82, 86, 76, 71, 72, 68, 77, 86, 68, 83, 84, 71, 81, 87 z-score for midterm: 1.857 z-score for final: 1.181 Based on the z-scores calculated above, which of Jaymes's grades is more unusual, the midterm grade or the final exam grade? Select the correct answer below: A. The absolute value of the z-score for the final exam grade is greater than for the midterm grade, so the final exam grade is more unusual. B. The absolute value of the z-score for the midterm exam grade is less than for the final grade, so the midterm grade is more unusual. C. The absolute value of the z-score for the midterm exam grade is greater than for the final grade, so the midterm grade is more…
A researcher wants to determine if the number of years of education for a parent correlates with the number of years of education for their child. The table shows the number of years of education of the parent and the number of years of education of their child for a random sample of 7. Years of Education of Parent: 13, 9, 12, 10, 12, 10, 12 Years of Education of their Child: 15, 11, 10, 16, 17, 12, 17 Conduct a hypothesis test to determine if there is a significant linear correlation between the two variables. Use α = 0.05. If there is a significant linear correlation between the variables, determine the regression equation. There is a significant correlation between the variables and the regression equation is y' = 5.333 + 0.777x There is a significant correlation between the variables and the regression equation is y' = 0.777 + 5.333x There is not a significant correlation between the variables, so the regression equation should not be determined. There is a significant…
Find the mean,median,and mode for the following frequency distribution table x 5,4,3,2,1,0 f 2,5,2,3,0,2
A recent study of 50 U.S. chess players details such things as the number of years the players have been active and the chess ratings of the players. (A chess rating is a number, with a higher number indicating greater expertise.) The chess rating data for the sample of 50 players are summarized in the following histogram. Frequency 15- 10+ 1 0.8 0.6 04 02 300 0 Based on the histogram, draw the ogive (the cumulative relative frequency polygon) for the sample data. Cumulative relative frequency 0.00 3 300 700 7 1100 1500 Chess rating 000 700 15 0.00 7 1100 1900 2300 2700 000 1500 Chess rating 0.00 1900 0.00 2300 [0.00 2700 X 2 E E B n
A government agency computed the proportion of U.S. residents who lived in each of four geographic regions in a particular year. Then a simple random sample was drawn of 1000 people living in the United States in the current year. The following table presents the results. Region Past YearProportion ObservedCounts Northeast 0.171 150 Midwest 0.245 235 South 0.357 398 West 0.227 217 Send data to Excel Can you conclude that the proportions of people living in the various regions changed between the current year and the past year? Use the 0.05 level of significance and the P-value method with the TI-84 Plus calculator. What the P value?
Data was collected for 161 randomly selected 10 minute intervals. For each ten-minute interval, the number of people entering the atrium of a large mall were recorded. The data is summarized in the table below. Number of Guests Frequency 220 – 239 5 240 – 259 35 260 – 279 80 280 – 299 27 300 – 319 14 What is the class width for this GFDT?Class width =
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
The mean number of sick days an employee takes per year is believed to be about 10.5. Members of a personnel department do not believe this figure. They randomly survey ten employees. The number of sick days they took for the past year are as follows: 12; 4; 15; 3; 11; 8; 6; 8; 2; 9. Let x = the number of sick days they took for the past year. Should the personnel team believe that the mean number is ten?
Last school year, the student body of a local university consisted of 35% freshmen, 24% sophomores, 26% juniors, and 15% seniors. A sample of 300 students taken from this year's student body showed the following number of students in each classification. Freshmen 90 Sophomores 60 Juniors 90 Seniors 60 We are interested in determining whether or not there has been a significant change in the classifications between the last school year and this school year. The calculated value for the test statistic equals a. 0.5444 b. 2.789 c. 10.989 d. 15.231

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