Customer Distribution by Weekday: A drop-in auto repair shop staffs the same number of mechanics on every weekday (weekends are not counted here). One of the mechanics thinks this is a bad idea because he suspects the number of customers is not evenly distributed across these days. For a sample of 289 customers, the counts by weekday are given in the table. Number of Customers by Day (n = 289) Tuesday Monday Wednesday Thursday Friday Count 41 44 57 75 72 The Test: Test the claim that the number of customers is not evenly distributed across the five weekdays. Test this claim at the 0.01 significance level. (a) What is the null hypothesis for this test in terms of the probabilities of the outcomes? O Họ: None of the probabilities are equal to 1/5. O Hg: Pmon 0.41, Pue 0.44, Pwed- 0.57, Pthur- 0.75, Ptri- 0.72. O Họ: At least one of the probabilities doesn't equal 1/5. O Hg: Pmon = Ptue = Pwed = Phur = Pri = 1/5. (b) What is the value of the test statistic? Round to 3 decimal places unless your software automatically rounds to 2 decimal places. (c) Use software to get the P-value of the test statistic. Round to 4 decimal places unless your software automatically rounds to 3 decimal places. P-value = (d) What the conclusion regarding the null hypothesis? O reject Ho O fail to reject Hg (e) Choose the appropriate concuding statement. O we have proven that the number of customers is evenly distributed across the five weekdays. O The data supports the claim that the number of customers is not evenly distributed across the five weekdays. O There is not enough data to support the claim that the number of customers is not evenly distributed across the five weekdays.
Customer Distribution by Weekday: A drop-in auto repair shop staffs the same number of mechanics on every weekday (weekends are not counted here). One of the mechanics thinks this is a bad idea because he suspects the number of customers is not evenly distributed across these days. For a sample of 289 customers, the counts by weekday are given in the table. Number of Customers by Day (n = 289) Tuesday Monday Wednesday Thursday Friday Count 41 44 57 75 72 The Test: Test the claim that the number of customers is not evenly distributed across the five weekdays. Test this claim at the 0.01 significance level. (a) What is the null hypothesis for this test in terms of the probabilities of the outcomes? O Họ: None of the probabilities are equal to 1/5. O Hg: Pmon 0.41, Pue 0.44, Pwed- 0.57, Pthur- 0.75, Ptri- 0.72. O Họ: At least one of the probabilities doesn't equal 1/5. O Hg: Pmon = Ptue = Pwed = Phur = Pri = 1/5. (b) What is the value of the test statistic? Round to 3 decimal places unless your software automatically rounds to 2 decimal places. (c) Use software to get the P-value of the test statistic. Round to 4 decimal places unless your software automatically rounds to 3 decimal places. P-value = (d) What the conclusion regarding the null hypothesis? O reject Ho O fail to reject Hg (e) Choose the appropriate concuding statement. O we have proven that the number of customers is evenly distributed across the five weekdays. O The data supports the claim that the number of customers is not evenly distributed across the five weekdays. O There is not enough data to support the claim that the number of customers is not evenly distributed across the five weekdays.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Transcribed Image Text:Customer Distribution by Weekday: A drop-in auto repair shop staffs the same number of mechanics on every weekday (weekends are not counted here). One of the mechanics thinks this is a bad idea because he suspects the number of customers is not evenly
distributed across these days. For a sample of 289 customers, the counts by weekday are given in the table.
Number of Customers by Day (n = 289)
Monday
Tuesday
Wednesday
Thursday
Friday
Count
41
44
57
75
72
The Test: Test the claim that the number of customers is not evenly distributed across the five weekdays. Test this claim at the 0.01 significance level.
(a) What is the null hypothesis for this test in terms of the probabilities of the outcomes?
O Ho: None of the probabilities are equal to 1/5.
O Hg: Pmon = 0.41, Ptue = 0.44, Pwed = 0.57, pPthur = 0.75, Ptri = 0.72.
O Ho: At least one of the probabilities doesn't equal 1/5.
O Hg: Pmon = Ptue = Pwed = Puthur = Ptri = 1/5.
(b) What is the value of the test statistic? Round to 3 decimal places unless your software automatically rounds to 2 decimal places.
(c) Use software to get the P-value of the test statistic. Round to 4 decimal places unless your software automatically rounds to 3 decimal places.
P-value =
(d) What is the conclusion regarding the null hypothesis?
O reject Ho
O fall to reject Ho
(e) Choose the appropriate concluding statement.
O we have proven that the number of customers is evenly distributed across the five weekdays.
O The data supports the claim that the number of customers is not evenly distributed across the five weekdays.
O There is not enough data to support the claim that the number of customers is not evenly distributed across the five weekdays.
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