**Problem 22 of 50**Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the product of the E2 reaction shown below.Include all lone pairs and charges as appropriate. Ignore byproducts.**Diagram Explanation:**The diagram shows a reaction mechanism for an E2 elimination reaction. In the structure, a cyclohexane ring is present with a bromine (Br) substituent attached and a hydrogen atom (H) on an adjacent carbon. The electron flow is indicated by curved arrows:- The first arrow shows the lone pair on the oxygen of tert-butoxide (\( \text{O}^{-}\text{-tBu} \)) attacking the hydrogen (H).- The second arrow depicts the C-H bond breaking and forming a double bond between two carbon atoms.- The third arrow represents the departure of the bromine atom as a leaving group (\( \text{Br}^- \)).Reagents and Conditions:- **tBuOH (tert-Butanol)**- **Heat**Select to Draw the E2 Product.

Answered: Image /qna-images/answer/fe7d77da-10b4-4d3a-ae5a-20ab750c41de.jpg

Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the product of the E2 reaction shown below. Include all lone pairs and charges as appropriate. Ignore byproducts. H₂C H 0:0: -tBu tBuOH o

Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the product of the E2 reaction shown below. Include all lone pairs and charges as appropriate. Ignore byproducts. H₂C H 0:0: -tBu tBuOH o

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Problem 22 of 50**

Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the product of the E2 reaction shown below.

Include all lone pairs and charges as appropriate. Ignore byproducts.

**Diagram Explanation:**
The diagram shows a reaction mechanism for an E2 elimination reaction. In the structure, a cyclohexane ring is present with a bromine (Br) substituent attached and a hydrogen atom (H) on an adjacent carbon. The electron flow is indicated by curved arrows:
- The first arrow shows the lone pair on the oxygen of tert-butoxide (\( \text{O}^{-}\text{-tBu} \)) attacking the hydrogen (H).
- The second arrow depicts the C-H bond breaking and forming a double bond between two carbon atoms.
- The third arrow represents the departure of the bromine atom as a leaving group (\( \text{Br}^- \)).

Reagents and Conditions:
- **tBuOH (tert-Butanol)**
- **Heat**

Select to Draw the E2 Product.

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