Current Attemptin Progress Each resistor in the three circuits in the drawing has the same resistance R, and the batteries have the same voltage V. The values for R and V are 80 and 6.0 V, respectively. Determine the total power delivered by the battery in each of the three circuits. R www R R R www www R R R R wwwww wwwww V V Circuit A Circuit B R R R w [www] www F PA= i V Circuit C
Current Attemptin Progress Each resistor in the three circuits in the drawing has the same resistance R, and the batteries have the same voltage V. The values for R and V are 80 and 6.0 V, respectively. Determine the total power delivered by the battery in each of the three circuits. R www R R R www www R R R R wwwww wwwww V V Circuit A Circuit B R R R w [www] www F PA= i V Circuit C
Chapter10: Direct-current Circuits
Section: Chapter Questions
Problem 24P: A person with body resistance between his hands of 10.0k accidentally grasps the terminals of...
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![**Current Attempt in Progress**
Each resistor in the three circuits in the drawing has the same resistance \( R \), and the batteries have the same voltage \( V \). The values for \( R \) and \( V \) are 8 \(\Omega\) and 6.0 V, respectively. Determine the total power delivered by the battery in each of the three circuits.
### Diagram Descriptions:
#### Circuit A:
- Top part: Two resistors \( R \) are in series.
- Bottom part: Two resistors \( R \) are in series.
- The top and bottom series combinations are connected in parallel.
- A battery with voltage \( V \) is connected across the parallel network.
#### Circuit B:
- There are three branches.
- Each branch contains two resistors \( R \) in series.
- The three branches are connected in parallel.
- A battery with voltage \( V \) is connected across the parallel branches.
#### Circuit C:
- The top part has one single resistor \( R \).
- The middle part, below the top resistor, has two resistors \( R \) in parallel.
- The bottom part consists of the parallel combination in the middle, connected in series with one resistor \( R \).
- A battery with voltage \( V \) is connected across this complex network.
### Power Calculation:
The power delivered by the battery in each circuit can be calculated using the formula:
\[ P = \frac{V^2}{R_{eq}} \]
Where:
- \( P \) is the total power.
- \( V \) is the voltage of the battery.
- \( R_{eq} \) is the equivalent resistance of the circuit.
Enter your values for \( P_A \), \( P_B \), and \( P_C \) after calculating the equivalent resistance for each circuit.
\[
P_A = \quad \text{(Your Answer)}
\]
\[
P_B = \quad \text{(Your Answer)}
\]
\[
P_C = \quad \text{(Your Answer)}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12bd8fce-6c39-4b5e-b612-a1c938c44a1c%2Fd391ff5b-5fcc-4ac0-8840-4b3d4a9cd66d%2F9uuod8t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Current Attempt in Progress**
Each resistor in the three circuits in the drawing has the same resistance \( R \), and the batteries have the same voltage \( V \). The values for \( R \) and \( V \) are 8 \(\Omega\) and 6.0 V, respectively. Determine the total power delivered by the battery in each of the three circuits.
### Diagram Descriptions:
#### Circuit A:
- Top part: Two resistors \( R \) are in series.
- Bottom part: Two resistors \( R \) are in series.
- The top and bottom series combinations are connected in parallel.
- A battery with voltage \( V \) is connected across the parallel network.
#### Circuit B:
- There are three branches.
- Each branch contains two resistors \( R \) in series.
- The three branches are connected in parallel.
- A battery with voltage \( V \) is connected across the parallel branches.
#### Circuit C:
- The top part has one single resistor \( R \).
- The middle part, below the top resistor, has two resistors \( R \) in parallel.
- The bottom part consists of the parallel combination in the middle, connected in series with one resistor \( R \).
- A battery with voltage \( V \) is connected across this complex network.
### Power Calculation:
The power delivered by the battery in each circuit can be calculated using the formula:
\[ P = \frac{V^2}{R_{eq}} \]
Where:
- \( P \) is the total power.
- \( V \) is the voltage of the battery.
- \( R_{eq} \) is the equivalent resistance of the circuit.
Enter your values for \( P_A \), \( P_B \), and \( P_C \) after calculating the equivalent resistance for each circuit.
\[
P_A = \quad \text{(Your Answer)}
\]
\[
P_B = \quad \text{(Your Answer)}
\]
\[
P_C = \quad \text{(Your Answer)}
\]
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