PoliciesCurrent Attempt in ProgressA wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total mass of thewagon, rider, and rock is 93.2 kg. The mass of the rock is 0.315 kg. Initially the wagon is rolling forward at a speed of 0.456 m/s. Thenthe person throws the rock with a speed of 16.6 m/s. Both speeds are relative to the ground. Find the speed of the wagon after the rockis thrown (a) directly forward in one case and (b) directly backward in another.(a) v = i(b) v =ieTextbooks

We are given total mass of the system. We are also given the mass of the rock. When the rock is thrown, all the forces are internal. Hence the momentum remains conserved. We apply this conservation of momentum to find the speed of wagon when initial speed is given.Mass of whole system M=93.2kg Mass of rock is m=0.315kg The mass of person and wagon system is m'=M-mm'=93.2-0.315m'=92.885kg Initial velocity of system is u=0.456m/s Velocity of rock is v=16.6 m/s Let the velocity of wagon be v'. Hence by conservation of momentum, Mu=mv+m'v'92.885v'=Mu-mv92.885v'=93.2×0.456-0.315×16.6v'=37.270292.885v'=0.401 m/s Hence speed of wagon is 0.401 m/s forward.Initial velocity of system is u=0.456m/s Velocity of rock is v=-16.6 m/s Let the velocity of wagon be v'. Hence by conservation of momentum, Mu=mv+m'v'92.885v'=Mu-mv92.885v'=93.2×0.456+0.315×16.6v'=47.728292.885v'=0.514 m/s Hence speed of wagon is 0.514 m/s forward.

Answered: Current Attempt in Progress A wagon is…