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Current 450 Problems 9.8 A three phase Ihe be tween phase conductors of 4 m. Each con ductor has has Legui latesal) spacing with separa bon d's tance radius of 1.5cm. a De tesmine: a) The inductance ger phase in mH Jmi I'= (1.5x10-2) en Inductance res phase of 3ø = 2x10-7 In GMD -1/4 > 0. 011 68 M GMD= (43)"B = 4, La= 2x107 In - 1.167 X106H)m 0.o1 68 (). 16 7 x 10-* Cwim] x 1o* = I.167x l0[mtH/m] (1. 167 x10[m H /m]) *lo00 - 1.167 mH/ km (1.167 mH /km) x 1.6 1. 8672 mH /me The inductance per phuse is | 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in r /km and Do I need GMB (geometric mean radius) to solve ?

Current 450 Problems 9.8 A three phase Ihe be tween phase conductors of 4 m. Each con ductor has has Legui latesal) spacing with separa bon d's tance radius of 1.5cm. a De tesmine: a) The inductance ger phase in mH Jmi I'= (1.5x10-2) en Inductance res phase of 3ø = 2x10-7 In GMD -1/4 > 0. 011 68 M GMD= (43)"B = 4, La= 2x107 In - 1.167 X106H)m 0.o1 68 (). 16 7 x 10-* Cwim] x 1o* = I.167x l0[mtH/m] (1. 167 x10[m H /m]) *lo00 - 1.167 mH/ km (1.167 mH /km) x 1.6 1. 8672 mH /me The inductance per phuse is | 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in r /km and Do I need GMB (geometric mean radius) to solve ?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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I need help to find the inductive reactance per phase in the following 3 phase line problem. I just need help with part b of the question.
Current 450 Problems has Lequilatesal spacing 9.8 A three phase line be tween phase conductors with of 4 M. Fach separa ton di's tance radus of 1.5cm. con ductor has a De termine: a) The inductance ger phase in mH Imi -1/4 s'= (1.5x102)e" > 0. o 11 68m Inductance rer phase of 3ø = 2x10-7 In GMD GMD= (43)"B = 4, La= 2x107 In 1,167 x106H/m 0.0U 68 ().167 x 10 * [wim3) x lo* = 167y lo[nH/m] (1. 167 x10:$ [m H/m])) ×lo00 - 1.167 mH/km (1.167 mH /km) x 1-6= 1, 8672 mA /mb The inductance per phuse is 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in /km and /mi Do I need GMR (geometric mean radius) to solve ?
Transcribed Image Text:Current 450 Problems has Lequilatesal spacing 9.8 A three phase line be tween phase conductors with of 4 M. Fach separa ton di's tance radus of 1.5cm. con ductor has a De termine: a) The inductance ger phase in mH Imi -1/4 s'= (1.5x102)e" > 0. o 11 68m Inductance rer phase of 3ø = 2x10-7 In GMD GMD= (43)"B = 4, La= 2x107 In 1,167 x106H/m 0.0U 68 ().167 x 10 * [wim3) x lo* = 167y lo[nH/m] (1. 167 x10:$ [m H/m])) ×lo00 - 1.167 mH/km (1.167 mH /km) x 1-6= 1, 8672 mA /mb The inductance per phuse is 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in /km and /mi Do I need GMR (geometric mean radius) to solve ?
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