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cturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assune the life spans of the tires are normally distributed. You select 100 tires at nd test them. The mean life span is 47,843 miles. Assume o = 900. Complete parts (a) through (c). ming the manufacturer's claim is correct, what is the probability that the mean of the sample is 47,843 miles or less? und to four decimal places as needed.) g your answer from part (a), what do you think of the manufacturer's claim? im is because the sample mean V be considered unusual since it V within the range of a usual event, namely within of the mean of the sample means. uming the manufacturer's claim is true, would it be unusual to have an individual tire with a life span of 47.843 miles? Why or why not? because 47,843 within the range of a usual event, namely within of the mean for an individual tire.

cturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assune the life spans of the tires are normally distributed. You select 100 tires at nd test them. The mean life span is 47,843 miles. Assume o = 900. Complete parts (a) through (c). ming the manufacturer's claim is correct, what is the probability that the mean of the sample is 47,843 miles or less? und to four decimal places as needed.) g your answer from part (a), what do you think of the manufacturer's claim? im is because the sample mean V be considered unusual since it V within the range of a usual event, namely within of the mean of the sample means. uming the manufacturer's claim is true, would it be unusual to have an individual tire with a life span of 47.843 miles? Why or why not? because 47,843 within the range of a usual event, namely within of the mean for an individual tire.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A manufacturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 47,843 miles. Assume o = 900. Complete parts (a) through (c). (a) Assuming the manufacturer's claim is correct, what is the probability that the mean of the sample is 47,843 miles or less? (Round to four decimal places as needed.) (b) Using your answer from part (a), what do you think of the manufacturer's claim? The claim is V because the sample mean be considered unusual since it V within the range of a usual event, namely within of the mean of the sample means. (c) Assuming the manufacturer's claim is true, would it be unusual to have an individual tire with a life span of 47,843 miles? Why or why not? , because 47,843 V within the range of a usual event, namely within V of the mean for an individual tire.
Transcribed Image Text:A manufacturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 47,843 miles. Assume o = 900. Complete parts (a) through (c). (a) Assuming the manufacturer's claim is correct, what is the probability that the mean of the sample is 47,843 miles or less? (Round to four decimal places as needed.) (b) Using your answer from part (a), what do you think of the manufacturer's claim? The claim is V because the sample mean be considered unusual since it V within the range of a usual event, namely within of the mean of the sample means. (c) Assuming the manufacturer's claim is true, would it be unusual to have an individual tire with a life span of 47,843 miles? Why or why not? , because 47,843 V within the range of a usual event, namely within V of the mean for an individual tire.
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