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- Analyse Verilog code in Figure 1 and modify the code to fulfil the following conditions:a) Add two more states: state C with state code 10, and state D with state code 11.b) State C will transit to state D if input X is 0 (output Z is 0), but it will remain in stateC if input X is 1 (output Z is 0).c) State D will transit to state A if input X is 0 (output Z is 0), and it will transit to stateB if input X is 1 (output Z is 1).how to do?A sequential circuit has three FF, A, B and C; one input x and one output y. The state diagram is shown below. The circuit is to be designed by treating the unused states as don't care conditions. Analyze the circuit obtained from the design to determine the effect of unused states. a. Use T FF in the design b. Use JK FF in the design. 0/0 001 1/1 0/0 1/0 100 011 0/0 1/1 1/1 \0/0 (010 1/1 000
- Q7. Write the Boolean equations and draw the logic diagram of the circuit whose outputs are defined by the following truth table: Table P2.27 1 0 1 1 0 1 1 0 1 0 1 0 a 0 0 0 0 1 1 1 b 0 0 1 1 0 0 1 C 0 1 0 1 0 1 Q8. Design a logic circuit whose output is HIGH only when a majority of inputs A, B, and Care High.Question 5 The truth table below describes a boolean function y(y1, y2, y3) with 3 input boolean variables. Y₁ 0 0 0 0 1 1 1 1 Describe the logic of this function. Y2 1 1 0 0 1 1 Y3 0 1 O O - O 0 1 1 y O O O - O - 1 1 1 15) Draw the state diagram for: Next State Output A(t+1) B(t+1) y(t) 0 0 0 0 1 0 0 1 1 0 0 1 0 0 0 1 0 0 Present State Input x(t) 0 1 0 1 A(t) B(t) 0 0 0 0 0 1 0 1 1 1 1 1 0 0 1 1 0 1 0 1 0 1 0 1 0 1
- I need help with thisWhat is the logic equation for the output Z for the state diagram of the code sequence detector, if the following state assignments are given: a = 00, b = 01, c = 11, d = 10. * O z = X'Y1Y2 O z = XY1'Y2' O z = XY1'Y2 Z = X'Y1Y2' O z = XY1Y2Draw the UML state-transition dlagram equivalent to the following state-transition table, which lists all the states, all possible events, and the resulting state Start state is PSUT. Current State Event Next State PSUT Input 'A JUST PSUT Input 'B' PSUT JUST Input 'C' PSUT JUST Input 'B' HU HU Input 'A' JUST HU Input 'C' PSUT