In Java 4:23 PA LTE ll 75%Cs101: Lab #14Exceptions Part IWrite a Java program that repeatedly accepts two integers from the keyboard and prints the quotient tothe console. Your code must adhere to the follow specifications:The user must enter 0 for both the numerator and denominator to exit the program.You must read the input values using the scanner's next () method and then convert to aprimitive integer using Integer.parseInt. In case of an exception (when converting thestring to an integer), the program must (1) print the corresponding stack trace(printStackTrace) and (2) reset the Scanner object.The program must catch division by zero exceptions and print a corresponding message in caseone occurs. The error should not be printed if the user intends to exit.

According to the information given:- We have to create the division program in which the we take repeat user input and give quotient as an output.import java.util.Scanner; class Main{ public static void main(String args[]){ Scanner sc = new Scanner(System.in); int numerator,denominator; //infinite loop while(true){ try{ //get numerator from user System.out.print("Enter numerator:"); numerator = Integer.parseInt(sc.next()); //get denominator from user System.out.print("Enter denominator:"); denominator = Integer.parseInt(sc.next()); //check if both are zero to exit the loop if(numerator==0 && denominator==0){ break; } else{ //otherwise print quotient System.out.println(numerator/denominator); } } //catch NumberFormatException execption and print stack trace catch(NumberFormatException e){ e.printStackTrace();} //catch divide by zero exception and print corresponding message catch(ArithmeticException e){ System.out.println("Division by zero error");}}}}Enter numerator:150Enter denominator:1212Enter numerator:159Enter denominator:0Division by zero errorEnter numerator:789Enter denominator:4561Enter numerator:321654Enter denominator:4561230Enter numerator: