CRYPTOGRAPHY Let's consider A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 be the coding matrix [1 1 11 A = 1 12 12 3 5. Get the inverse of matrix (decoder matrix) and use it to decode the message 52 68 171 5 7 17 30 39 99 9 13 31 52 79 205 Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector ANSWER
CRYPTOGRAPHY Let's consider A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 be the coding matrix [1 1 11 A = 1 12 12 3 5. Get the inverse of matrix (decoder matrix) and use it to decode the message 52 68 171 5 7 17 30 39 99 9 13 31 52 79 205 Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector ANSWER
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![CRYPTOGRAPHY
Let's consider
A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
be the coding matrix
1 1 1]
A = 1 1 2
L2 3 5
**
Get the inverse of matrix (decoder matrix) and use it to decode the message
52 68 171 5 7 17 30 39 99 9 13 31 52 79 205
Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector
ANSWER](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcfb92d0-f697-437d-b4fd-907fc9ead1e6%2Fc74d22d7-5f3c-4b26-9e56-408745143921%2Fwbfrix_processed.png&w=3840&q=75)
Transcribed Image Text:CRYPTOGRAPHY
Let's consider
A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
be the coding matrix
1 1 1]
A = 1 1 2
L2 3 5
**
Get the inverse of matrix (decoder matrix) and use it to decode the message
52 68 171 5 7 17 30 39 99 9 13 31 52 79 205
Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector
ANSWER
![Find two numbers whose sum is 30 and the difference is 19
Find the smallest of the numbers
Note: Solve using Cramer's rule-manual](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcfb92d0-f697-437d-b4fd-907fc9ead1e6%2Fc74d22d7-5f3c-4b26-9e56-408745143921%2Fcpet3w_processed.png&w=3840&q=75)
Transcribed Image Text:Find two numbers whose sum is 30 and the difference is 19
Find the smallest of the numbers
Note: Solve using Cramer's rule-manual
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