CRYPTOGRAPHY Let's consider A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 be the coding matrix [1 1 11 A = 1 12 12 3 5. Get the inverse of matrix (decoder matrix) and use it to decode the message 52 68 171 5 7 17 30 39 99 9 13 31 52 79 205 Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector ANSWER
CRYPTOGRAPHY Let's consider A B C D E F G H I J K L M N Ñ O P Q R S T V W X Y Z 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 be the coding matrix [1 1 11 A = 1 12 12 3 5. Get the inverse of matrix (decoder matrix) and use it to decode the message 52 68 171 5 7 17 30 39 99 9 13 31 52 79 205 Note: Group three by three and place them as a column vector, then multiply the inverse matrix with the column vector ANSWER
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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