(CRT) 3 Satellites will cross Hawaii meridian tonight. The first at 0300, second at 0700 and third at 1100. Each sat has a different period, i.e., time per one revolution around the Earth, given by: Sat 1: t1 = 11 hrs Sat 2: t2 = 19 hrs Sat 3: t3 = 29 hrs X = # of hours elapsed from midnight tonight until all 3 sats cross simultaneously Find X and express in days/hours

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter9: Real Numbers And Right Triangles
Section9.8: The Sine And Cosine Ratios
Problem 16E
Question
The problem involves three satellites that will cross the Hawaii meridian tonight. The first satellite crosses at 0300, the second at 0700, and the third at 1100. Each satellite has a different orbital period, which is the time it takes for one complete revolution around the Earth. The orbital periods are given as follows:

- Satellite 1: t1 = 11 hours
- Satellite 2: t2 = 19 hours
- Satellite 3: t3 = 29 hours

The objective is to find \( x \), which represents the number of hours elapsed from midnight tonight until all three satellites cross the meridian simultaneously again. The result should be expressed in days and hours.
Transcribed Image Text:The problem involves three satellites that will cross the Hawaii meridian tonight. The first satellite crosses at 0300, the second at 0700, and the third at 1100. Each satellite has a different orbital period, which is the time it takes for one complete revolution around the Earth. The orbital periods are given as follows: - Satellite 1: t1 = 11 hours - Satellite 2: t2 = 19 hours - Satellite 3: t3 = 29 hours The objective is to find \( x \), which represents the number of hours elapsed from midnight tonight until all three satellites cross the meridian simultaneously again. The result should be expressed in days and hours.
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