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crosoft.MicrosoftEdge_8wekyb3d8bbwe/TempState/Downloads/PHY2054 Test2 Sample_solution_Chap19,20 21%20,. G TVagneuc TICIu, MaynGLIC Torces, Rigrit Tand rui 4. Three long, parallel wires each carry current I = 10 A in the directions shown in the figure. The separation between adjacent wires is d = 10 cm. a) What is the net magnetic field (magnitude and direction) due to wires #1 and # 3 at the wire #2 position? b) What is the net magnetic force (magnitude and direction) on wire #2? Math 1 wire #1 wire #2 B B3 wire #3 a) Both fields are out and equal. B, = B, = Hol/(2 rd) B, B, = (4xx107)(10)( 2 7(0.1)) = 2x10 T %3D Bnet = B, + B, = 4x10 T, out of page. b) F = 1 LBneSsin90° vector L, and Bner are perpendicular. Here we can only calculate the force length since we don't have the length of the wire. FL = IBnet = 4x10 Nm, direction: downward.

crosoft.MicrosoftEdge_8wekyb3d8bbwe/TempState/Downloads/PHY2054 Test2 Sample_solution_Chap19,20 21%20,. G TVagneuc TICIu, MaynGLIC Torces, Rigrit Tand rui 4. Three long, parallel wires each carry current I = 10 A in the directions shown in the figure. The separation between adjacent wires is d = 10 cm. a) What is the net magnetic field (magnitude and direction) due to wires #1 and # 3 at the wire #2 position? b) What is the net magnetic force (magnitude and direction) on wire #2? Math 1 wire #1 wire #2 B B3 wire #3 a) Both fields are out and equal. B, = B, = Hol/(2 rd) B, B, = (4xx107)(10)( 2 7(0.1)) = 2x10 T %3D Bnet = B, + B, = 4x10 T, out of page. b) F = 1 LBneSsin90° vector L, and Bner are perpendicular. Here we can only calculate the force length since we don't have the length of the wire. FL = IBnet = 4x10 Nm, direction: downward.

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How is the net magnetic force is downward for Wire 2?

crosoft.MicrosoftEdge_8wekyb3d8bbwe/TempState/Downloads/PHY2054 Test2 Sample_solution_Chap19,20 21%20,. G TVagneuc TICIu, MaynGLIC Torces, Rigrit Tand rui 4. Three long, parallel wires each carry current I = 10 A in the directions shown in the figure. The separation between adjacent wires is d = 10 cm. a) What is the net magnetic field (magnitude and direction) due to wires #1 and # 3 at the wire #2 position? b) What is the net magnetic force (magnitude and direction) on wire #2? Math 1 wire #1 wire #2 B B3 wire #3 a) Both fields are out and equal. B, = B, = Hol/(2 rd) B, B, = (4xx107)(10)( 2 7(0.1)) = 2x10 T %3D Bnet = B, + B, = 4x10 T, out of page. b) F = 1 LBneSsin90° vector L, and Bner are perpendicular. Here we can only calculate the force length since we don't have the length of the wire. FL = IBnet = 4x10 Nm, direction: downward.
Transcribed Image Text:crosoft.MicrosoftEdge_8wekyb3d8bbwe/TempState/Downloads/PHY2054 Test2 Sample_solution_Chap19,20 21%20,. G TVagneuc TICIu, MaynGLIC Torces, Rigrit Tand rui 4. Three long, parallel wires each carry current I = 10 A in the directions shown in the figure. The separation between adjacent wires is d = 10 cm. a) What is the net magnetic field (magnitude and direction) due to wires #1 and # 3 at the wire #2 position? b) What is the net magnetic force (magnitude and direction) on wire #2? Math 1 wire #1 wire #2 B B3 wire #3 a) Both fields are out and equal. B, = B, = Hol/(2 rd) B, B, = (4xx107)(10)( 2 7(0.1)) = 2x10 T %3D Bnet = B, + B, = 4x10 T, out of page. b) F = 1 LBneSsin90° vector L, and Bner are perpendicular. Here we can only calculate the force length since we don't have the length of the wire. FL = IBnet = 4x10 Nm, direction: downward.
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