-k/QNT 375T_55007971/chapter/5/section/3ST: Business Data Analytics home >vals for population proportionszyBooks catalogHelctivitiesCHALLENGE5.3.1: Confidence intervals for population proportions.ACTIVITYCritical values for quick reference during this activity.Confidence level Critical value0.90z* = 1.6450.95z* = 1.9600.99z* = 2.576353846 1423376.gx3zgy7Jump to level 1In a poll of 1000 randomly selected voters in a local election, 314 voters werein favor of school bond measures.What is the sample proportion p? Ex: 0.123:What is the margin of error m for the 90% confidence level? Ex: 0123pausebreakprt scsysrgF10F11F12deleteinsertF5F6F7F8F9と4&7backs8R.YUPD-ロD·D国

The sample size n is 1000 and the number of voters were in favor of school bond measures (x) is 314.

Answered: Critical values for quick reference…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Objective: Finding critical valuesThe critical value for a 80% confidence inverval for a one sample proportion with a sample size of 27 is 1.28 1.314 1.315 0.84
HW Score: 0%, O of 16 pts Question Help O The price-earnings ratios for all companies whose shares are traded on a specific stock exchange followa normal distribution with a standard deviston of 43 Arandom sample of these companies is selected in order to estimate the population mean price-earnings ratio Complete parts (a) through (c) a How large a sample is necessary in order to ensure that the probablity that the sample mean differs from the population mean by more than 1.1s less than 0 107 The sample size must be at least 42. (Type a whole number) b. Without doing the calculations, state whether a larger or smaller sample size compared to the sample sze in part (a) wouid be requred to guaranlee that the probability of the sample mean differing from the population mean by more than 1.1 is less than 0.05 Incorrect: O The sample size would need to be
na test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.4 and a standard deviation of 19.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? Omg/dL
Explain what this chart is showing.
The p-value for a t-statistic was .008. What is the best way to report the level of significance? p<.008 p<.05 p<.01 p<.001
What are the degrees of freedom and critical values for independent samples t-tests with a = 0.05; two-tailed; n =10, n2= 10 %3D Please write your critical value answer in the following format: (for a 2 tailed test) 1.234 and-1.234 (for a one tailed test) 1.234 or -1.234
??
Sales personnel for Skilling Distributors submit weekly reports listing the customer contacts made during the week. A sample of 15 weekly reports showed a sample mean of 19.5 customer contacts per week. The sample standard deviation was 5.2. Provide a 90% confidence interval for the population mean number of weekly customer contacts for the sales personnel.
6. A small company can employ 3 workers. Each worker independently stays on the job for an exponentially distributed time with a mean of one year and then quits. When a worker quits, it takes the company an exponentially distributed time with a mean of 1/10 of a year to hire a replacement for that worker (independently of how long it takes to replace other workers). If the company takes in $1000 per day in revenue when it has 3 workers, $800 per day when it has 2 workers, and $500 per day when it has 0 or 1 workers, what is the company's long-run average daily revenue?
Estimate of the proportion p for a 95% confidence with a sample size ? = 400 and point estimate ?̂= 0.4 Please provide it neatly with indicated given, formula, solution, and answer.
How is the sample size related to the margin of error and confidence level? What isthe impact of S.D. on sample size? Comments with justification. Also fill in theblanks showing necessary calculations in each case: Margin of error S .D. Confidence Level Sample Size 0.4274 5.33 95% ________ 0.8548. 4.79 ___________. 209 0.7948 ______ 90% 249 0.2129 5.79 __________. 2841 __________. 2.54 90% 3720
In a sampling distribution of means, variation is measured using what? OZ score Standard Error O Confidence Intervals O Mean of Means

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