Create the following table in your database with the following schema: Table: Users +- | Column Name 1 Туре +- | id | name | int I varcharI ----+ id is the primary key for this table. name is the name of the user. Table: Rides | Column Name 1 Туре +- | id I user_id I distance | int | int | int +- id is the primary key for this table. user_id is the id of the user who traveled the distance "distance". Add the following data to your tables: Input: Users table: +----- | id | name | 1 | 2 | 3 | 4 | Alice | Bob | Alex | Donald I Lee
Create the following table in your database with the following schema: Table: Users +- | Column Name 1 Туре +- | id | name | int I varcharI ----+ id is the primary key for this table. name is the name of the user. Table: Rides | Column Name 1 Туре +- | id I user_id I distance | int | int | int +- id is the primary key for this table. user_id is the id of the user who traveled the distance "distance". Add the following data to your tables: Input: Users table: +----- | id | name | 1 | 2 | 3 | 4 | Alice | Bob | Alex | Donald I Lee
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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i want the codes of create table and insert table only please

Transcribed Image Text:Create the following table in your database with the following schema:
Table: Users
| Column Name
| Туре
+-
+-
| int
| varchar |
| id
| name
+-
id is the primary key for this
table.
name is the name of the user.
Table: Rides
| Column Name
| туре
+-
| id
| user id
| distance
| int
| int
| int
+-
id is the primary key for this
table.
user id is the id of the user who traveled the distance "distance".
Add the following data to your tables:
Input:
Users table:
+------+
| id
| name
+-
| 1
| 2
| 3
| 4
| 7
| 13
| 19
| Alice
| Bob
| Alex
| Donald
| Lee
| Jonathan
| Elvis
+----
Rides table:
+------
| id
I user id
| distance |
+-----
+---
| 1
| 2
| 3
| 4
| 5
| 1
| 2
| 3
| 7
| 13
| 19
| 120
| 317
| 222
| 100
| 312
50
| 120
| 400
| 230
| 8
| 19
+-----

Transcribed Image Text:Return the result table ordered by travelled_distance in descending order, if two or more users traveled
the same distance, order them by their name in ascending order.
Hint: Use IFNULL(a,b) function in your select clause where a is the value that should be returned and
b is the value that should be returned if a is NULL.
The result should be:
Output:
| name
travelled distance
+--
| Elvis
| Lee
| Bob
| Jonathan | 312
| Alex
| Alice
| Donald
| 450
| 450
| 317
| 222
| 120
+-
Explanation:
Elvis and Lee traveled 450 miles, Elvis is the top traveler as his name is
alphabetically smaller than Lee.
Bob, Jonathan, Alex, and Alice have only one ride and we just order them by the
total distances of the ride.
Donald did not have any rides, the distance traveled by him is 0.
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