Create a table named 'EMPLOYEE' with the required fields (empno int, first_namevarchar(16), last_name varchar(16), hire_date date, salary int) and insert the followingrecords given below.Sample Data:empno | first_name | last_name | hire_date | sal1 | john| mathew| 2009-05-20 | 300002 | riya| roy| 2010-05-23 | 30000 ||2020-02-12 | 90000 ||3 | Leah| pv|Ensure that the 'EMPLOYEE' table contains, at the minimum, the provided records

I have provided a detailed answer in the Explanation section.Explanation:Here are the SQL queries to…

Answered: Create a table named 'EMPLOYEE' with…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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CREATE TABLE Employee( firstName char(30) , lastName char(30) , hireDate date ,empNo int , empInitial char(30) , years int ); Write the SQL syntax to create an insert statement for the employee table you created above.
List the names of all Staff members who hold a faculty position and have a salary of $45,000 or less. Show their names as their first name, followed by a space, and then their last name but sort the list alphabetically by last name and then first name. Hint: Check out the Position column in the Staff table. All staff members who do not hold a faculty position will get a bonus this year equal to 5% of their salary. List the names, current salary, and bonus amount for each Staff member (non-faculty) who is due a bonus. Show your list in order with the person receiving the highest bonus first.
1.CREATE TABLE contacts ( last_name VARCHAR(30) NOT NULL, first_name VARCHAR(25) NOT NULL, birthday DATE, CONSTRAINT contacts_pk PRIMARY KEY (last_name, first_name) ); Use insert query and insert the values and display the table.
Create a new table maned “Hiking” that includes TripID, NumPersons from Reservation table and Trip Type, Trip Name columns from Trip table where Trip type is “Hiking” .
For this problem create a (temporary) table called instructor_course_nums. Write a procedure that accepts an instructor ID as input. The procedure calculates the total number of course sections taught by that instructor, and adds a tuple to the temporary table consisting of the instructors ID number, name, and total courses taught - call these attributes: ID, name, and tot_courses. If the instructor already has an entry in the table,then the procedure makes sure the total number of courses taught in the temporary table is up-to-date. You must name your procedure: Written in PostgreSQL
Q5) What is the normalization of the following table, where the primary keys are underlined: Note: all the data in cells of the table are already atomic. OrderID Order Date 1006 1006 10/24/2010 1006 1007 10/24/2010 1007 10/24/2010 10/25/2010 10/25/2010 Customer Customer Customer ProductID Product ID Name Address Description 2 2 2 6 6 Value Furniture Value Furniture Value Furniture Plano, TX Plano, TX Plano, TX Furniture Boulder, Gallery CO Furniture Boulder, Gallery CO 7 5 4 11 Dining Table Writer's Desk Product Product Finish Standard Price 4-Dr Dresser Natural 800.00 Ash Cherry 325.00 Entertainment Natural 650.00 Center Maple 500.00 4 Entertainment Natural 650.00 Center Maple Ordered Quantity 2 2 1 4 3
Update table product to set the value of column productType equal to the corresponding id value in the table productType. This requires a SELECT * FROM productType: to see what the id value is for each type. For example, in my database a. 1|meat b. 2| seafood c. 3| vegetable d. 4 grain and rice e. 5 bakery
Create a table with the foll columns. nae of employee (NAME, variable character) Date of birth(DOB, date) Salary of employee(SALARY,integer) Department(DEPT, variable character) [Department :SALE,ACCT,MARKETING]
help please Create a table named BRANCH. The table has the following structureBRANCH_NUM decimal(2,0) NOT NULL default '0'BRANCH_NAME char(50) default NULLBRANCH_LOCATION char(50) default NULLNUM_EMPLOYEES decimal(2,0) deault NULL PRIMARY KEY (`BRANCH_NUM`) (Please type answer no write by hand)
MySQL CREATE TABLE students ( id INT PRIMARY KEY, first_name VARCHAR(50), last_name VARCHAR(50), age INT, major VARCHAR(50), faculty VARCHAR(50)); CREATE TABLE location ( id INT PRIMARY KEY, name VARCHAR(50), rooms INT); CREATE TABLE faculty ( id INT PRIMARY KEY, name VARCHAR(50), department_id INT); 4. Find the number of employees in each department who get no commission or have salary less than5000.5. Find the maximum salary of employees in each department that the employee was hired 15 yearsbefore now. *hint: user TIMESTAMPDIFF(<unit type>,<Date_value 1>,<Date_value 2>), the unitcan be YEAR, MONTH, DAY, HOUR, etc...6. Find the last name of all employees that were not hired on Tuesday *hint: (UseDATE_FORMAT() function amd the format you need is %W, also use UPPER()7. Find the number of employees in each department who have a manager.8. Find the number of employees for each manager whose employees' minimum salary is greaterthan 5000.9. Find the number of…
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Hi triggers Update and using Xampp and this table: CREATE TABLE MEMBER(STUDENT_ID CHAR(6) NOT NULL,CLUB_CODE VARCHAR(4) NOT NULL,MEMBER_DATE DATE NOT NULL,MEMBER_POSITION VARCHAR(15) NOT NULL,MEMBER_ATTENDANCE CHAR(2) NOT NULL,PRIMARY KEY (STUDENT_ID,CLUB_CODE),FOREIGN KEY (STUDENT_ID) REFERENCES STUDENT (STUDENT_ID) ON DELETE RESTRICT ON UPDATE CASCADE,FOREIGN KEY (CLUB_CODE) REFERENCES CLUB (CLUB_CODE) ON DELETE RESTRICT ON UPDATE CASCADE); INSERT INTO MEMBER VALUES('100027','C201','2020-03-25','Secretary','12'),('100027','C202','2020-04-11','Member','11'),('100032','C201','2020-02-23','President','12'),('100050','C201','2020-03-25','Member','10'),('100132','C202','2020-04-11','Treasurer','10'),('100074','C203','2020-04-09','President','12'),('100074','C204','2020-04-25','Treasurer','12'),('100051','C204','2020-04-25','Member','9'),('100064','C207','2020-04-25','Vice…

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