Create a public class GraphAnalysis that provides a single static method named isUndirected. isUndirected accepts an UnweightedGraph from cs1.graphs and hould return true if the graph is undirected and false otherwise. If the passed graph is null, throw an IllegalArgumentException. ach node in the graph has a set of neighbors that you can retrieve representing links rom that node to other nodes. If the graph is undirected, if there is a link from A to B ther here is also a link from B to A. So if B is a neighbor of A, then A should also be a neighbor of B. Note that you do not need to solve this problem recursively, since there is a concise terative solution. or reference, cs1.graphs.UnweightedGraph has the following public properties: 1 public class UnweightedGraph { public Set getNodes (); // returns all node in the graph 3 } 2 And csl.graphs.GraphNode has the following public properties: 1 public class GraphNode { public Object getValue(); // returns the value public Set getNeighbors(); // returns the neighbors of this node 3 4 }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Create a public class `GraphAnalysis` that provides a single `static` method named `isUndirected`. `isUndirected` accepts an `UnweightedGraph<?>` from `cs1.graphs` and should return `true` if the graph is undirected and `false` otherwise. If the passed graph is `null`, throw an `IllegalArgumentException`.

Each node in the graph has a set of neighbors that you can retrieve representing links from that node to other nodes. If the graph is undirected, if there is a link from A to B then there is also a link from B to A. So if B is a neighbor of A, then A should also be a neighbor of B.

Note that you do *not* need to solve this problem recursively, since there is a concise iterative solution.

For reference, `cs1.graphs.UnweightedGraph` has the following public properties:

```java
public class UnweightedGraph {
    public Set<GraphNode> getNodes(); // returns all nodes in the graph
}
```

And `cs1.graphs.GraphNode` has the following public properties:

```java
public class GraphNode {
    public Object getValue(); // returns the value
    public Set<GraphNode> getNeighbors(); // returns the neighbors of this node
}
```
Transcribed Image Text:Create a public class `GraphAnalysis` that provides a single `static` method named `isUndirected`. `isUndirected` accepts an `UnweightedGraph<?>` from `cs1.graphs` and should return `true` if the graph is undirected and `false` otherwise. If the passed graph is `null`, throw an `IllegalArgumentException`. Each node in the graph has a set of neighbors that you can retrieve representing links from that node to other nodes. If the graph is undirected, if there is a link from A to B then there is also a link from B to A. So if B is a neighbor of A, then A should also be a neighbor of B. Note that you do *not* need to solve this problem recursively, since there is a concise iterative solution. For reference, `cs1.graphs.UnweightedGraph` has the following public properties: ```java public class UnweightedGraph { public Set<GraphNode> getNodes(); // returns all nodes in the graph } ``` And `cs1.graphs.GraphNode` has the following public properties: ```java public class GraphNode { public Object getValue(); // returns the value public Set<GraphNode> getNeighbors(); // returns the neighbors of this node } ```
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