Create 1 Program in Python, to Solve two different Engineering Problems. Your two programs must include the following elements:
Create 1
Your two programs must include the following elements:
1. Welcome Message
2. Problem Description Message
(background, required inputs & expected results)
3. Set/Capture Input Data
4. Perform the Main Process
(corresponds to the Engineering Problem)
5. Display Results, feedback, and Comments
(Based on results)
6. Goodbye Message
Rules:
- You can select your Engineering Problems from the Engineering Problems Source document
- You must select two different Problems from the source document.
- You can select only available problems that were not already selected by another group,
selection is on first-come, first-serve basis.
- Problems Selection (booking) will be done in the Telegram Group.
- After 7 days, groups that did not select problems, will be assigned problems at random
Bonuses:
- Include Validation (whenever User input is involved)
- Solve Multiple Engineering Problems in one program (user can select from main menu)
- Add export data option to write results/findings into an external document
- Include Plotting/Visualization in your program (using graphics libraries)
- Add main menu options, i.e. select program, export data, plot data, restart, quit, etc.
- Use advanced/new concepts not taught in class
- Any other feature (code readability, good UI, Processing effects, etc.)
![*3-48. Determine the tension developed in cables AB, AC,
and AD required for equilibrium of the 150-kg crate.
B
0.3 m,
0.6 m
0.3 m
40.6 m
0,6 m
0.6 m
[A
0.9 m
D
Force Vectors: We can express each of the forces on the free-body diagram shown in Fig. (a) in Cartesian vector form as
(-0.6 – 0)i + (0.3 – 0)j + (0.6 – 0)k
FA = FAB
Fi+ FAnj
FAk
LV-0.6 – 0)² + (0.3 – 0)² + (0.6 – 0)²
(-0.6 – 0)i + (-0.6 – 0)j + (0.3 – 0)k
FAC = FAc
(-0.6 – 0)² + (-0.6 – 0)² + (0.3 – 0)²
FAD = FADİ
W = [-300k] N
Equations of Equilibrium: Equilibrium requires
EF = 0; FAn + FAc + FAp + W = 0
_2,
Fi-Fcj+ Fack + F,i + (-150(9.81)k) = 0
F
-Fk
+
AB
+ FAD
-F
F
AC
j+
F
- 300 k = 0
AB
AC
AB
AB
AC
Equating the i, j, and k components yields
· Fxc+ FAp = 0
(1)
AB
3
· Fxc = 0
(2)
AB
3
AC
FAB +
Fxc – 150(9.81) = 0
AC
3
(3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2ebf2d2-e51d-4921-8949-88495a7da542%2F0ea74fa0-5c3d-4787-b17a-490d039ce24a%2Fyadf89_processed.png&w=3840&q=75)
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