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c=R Figure P9.44 5 In the full-wave power supply shown in Figure P9.44 the diodes are 1N4001 general-purpose silicon diodes with a rated peak reverse voltage of 10 V and Vine = 156 cos(377t) n= 0.04231 V, = 0.2 V IL = 2.5 mA V = 5.1 V a. Determine the actual peak reverse voltage across the diodes. b. Explain why these diodes are or are not suitable for the specifications given.

c=R Figure P9.44 5 In the full-wave power supply shown in Figure P9.44 the diodes are 1N4001 general-purpose silicon diodes with a rated peak reverse voltage of 10 V and Vine = 156 cos(377t) n= 0.04231 V, = 0.2 V IL = 2.5 mA V = 5.1 V a. Determine the actual peak reverse voltage across the diodes. b. Explain why these diodes are or are not suitable for the specifications given.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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c=R Figure P9.44 5 In the full-wave power supply shown in Figure P9.44 the diodes are 1N4001
Transcribed Image Text:c=R Figure P9.44 5 In the full-wave power supply shown in Figure P9.44 the diodes are 1N4001
general-purpose silicon diodes with a rated peak reverse voltage of 10 V and Vine = 156 cos(377t) n= 0.04231 V, = 0.2 V IL = 2.5 mA V = 5.1 V a. Determine the actual peak reverse voltage across the diodes. b. Explain why these diodes are or are not suitable for the specifications given.
Transcribed Image Text:general-purpose silicon diodes with a rated peak reverse voltage of 10 V and Vine = 156 cos(377t) n= 0.04231 V, = 0.2 V IL = 2.5 mA V = 5.1 V a. Determine the actual peak reverse voltage across the diodes. b. Explain why these diodes are or are not suitable for the specifications given.
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