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Cout Count up Shift Left Load Sin CLK The functionality of the circuit is determined as follows: • If the load is activated (Load ='1') then the parallel input Iolilz is loaded into the circuit and with the rising edge of the clock appears on the output.

Cout Count up Shift Left Load Sin CLK The functionality of the circuit is determined as follows: • If the load is activated (Load ='1') then the parallel input Iolilz is loaded into the circuit and with the rising edge of the clock appears on the output.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you design this circuit for me based on the specifications

0, 0, 0, Cout Count up Shift Left Load Sin CLK The functionality of the circuit is determined as follows: • If the load is activated (Load ='1') then the parallel input lolilz is loaded into the circuit and with the rising edge of the clock appears on the output. • If the load is deactivated, then If the Shift Left ='1', the Sin is shifted into the circuit and with the rising edge of the clock the output changes from 0,0;0 to Sin 0,01. • If the Load='0' and shift Left='0', then if the Count up ='1', the output is incremented by 1 (If the output equals 111, then the next state output would be 000 and the Cout=1). IF count up ='0' and Shift Left ='0' and Load ='0' then no change appears on the output 1. Design the circuit using D-flipflops using the note lectures.
Transcribed Image Text:0, 0, 0, Cout Count up Shift Left Load Sin CLK The functionality of the circuit is determined as follows: • If the load is activated (Load ='1') then the parallel input lolilz is loaded into the circuit and with the rising edge of the clock appears on the output. • If the load is deactivated, then If the Shift Left ='1', the Sin is shifted into the circuit and with the rising edge of the clock the output changes from 0,0;0 to Sin 0,01. • If the Load='0' and shift Left='0', then if the Count up ='1', the output is incremented by 1 (If the output equals 111, then the next state output would be 000 and the Cout=1). IF count up ='0' and Shift Left ='0' and Load ='0' then no change appears on the output 1. Design the circuit using D-flipflops using the note lectures.
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