Could you help me to understand the solution? I don't know the meaning of (8 3,3,2)in the picture. Does it mean nCr? Why there are three numbers in r's position? How to calculate it? and I also need more detailed explanation of this solution. Thanks! Q: How many permutations in S8 have two cycles of length 3 and one of length 2? (You do not need to simplify your answer to an integer.) Solution is in the picture
Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
Could you help me to understand the solution? I don't know the meaning of (8 3,3,2)in the picture. Does it mean nCr? Why there are three numbers in r's position? How to calculate it? and I also need more detailed explanation of this solution. Thanks!
Q: How many permutations in S8 have two cycles of length 3 and one of length 2? (You do not need to simplify your answer to an integer.)
Solution is in the picture

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