Could I please get help ### Ratio CalculationTo find the ratio of \(\dfrac{A'B'}{AB}\):#### Diagram ExplanationThere is a coordinate graph where:- A is positioned at (2, 2),- B is positioned at (4, 2),- A' is positioned at (2, 6),- B' is positioned at (9, 3),- C is positioned at (4, 6),- C' is positoned at (10, 10).#### Steps to Calculate the Ratio1. Determine the length of segment \(AB\): - A (2, 2) to B (4, 2) - The difference in x-coordinates: \(4 - 2 = 2\). - Since both points share the same y-coordinate, the length of \(AB\) is 2 units.2. Determine the length of segment \(A'B'\): - A' (2, 6) to B' (9, 3) - Using the distance formula: \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\) - \(\sqrt{(9 - 2)^2 + (3 - 6)^2} = \sqrt{7^2 + (-3)^2} = \sqrt{49 + 9} = \sqrt{58}\).3. Find the ratio \(\dfrac{A'B'}{AB}\): - \(\dfrac{\sqrt{58}}{2}\)The options provided are:- 2- 3- 6- 12Based on our more detailed calculation, none of the given options match the exact calculation of the ratio. Double-check calculations and graph plotted points for more precision.

Name: Could I please get help ### Ratio CalculationTo find the ratio of \(\d
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Could I please get help ### Ratio CalculationTo find the ratio of \(\dfrac{A'B'}{AB}\):#### Diagram ExplanationThere is a coordinate graph where:- A is positioned at (2, 2),- B is positioned at (4, 2),- A' is positioned at (2, 6),- B' is positioned a