Please I need help with these questions Each of the following statements is an attempt to show that a given series is convergentor divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement,enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argumentis flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter1.)In(n)1. For all n > 2,and the series - converges, so by theComparison Test, the series EIn(n)converges.arctan(n)I, and the series E converges, so by the2n2. For all n > 1,arctan(n)Comparison Test, the series Econverges.1.3. For all n > 1,< 2, and the series 2E diverges, so by then In(n)Comparison Test, the seriesdiverges.п In(n)In(n)>1, and the series E diverges, so by the Comparison4. For all n > 2,Test, the series EIn(n)diverges.5. For all n > 2,and the series > converges, so by theComparison Test, the series En2-4n2 41converges.6. For all n > 2,n 52and the series 2Econverges, so by theComparison Test, the series >n3 5converges. Test each of the following series for convergence by either the Comparison Test or theLimit Comparison Test. If at least one test can be applied to the series, enter CONV if itconverges or DIV if it diverges. If neither test can be applied to the series, enter NA. (Note: thismeans that even if you know a given series converges by some other test, but the comparisontests cannot be applied to it, then you must enter NA rather than CONV.)cos(n) /nNAЗп + 6* cos (n) /n2.CONVn300 8n°n* + 3/nCONV3.8n8 – n3 +4003n3DIV4.nº + 6003n3CONV5.n4 + 6n=1

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Description: Please I need help with these questions Each of the following statements is an attempt to show that a given series is convergentor divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement,enter C (for "correct") if the

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Answered: cos(n) /n Зп + 6 0 cos? (n) /n NA 1.…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

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Please I need help with these questions

Each of the following statements is an attempt to show that a given series is convergent
or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement,
enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argument
is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter
1.)
In(n)
1. For all n > 2,
and the series - converges, so by the
Comparison Test, the series E
In(n)
converges.
arctan(n)
I, and the series E converges, so by the
2n
2. For all n > 1,
arctan(n)
Comparison Test, the series E
converges.
1.
3. For all n > 1,
< 2, and the series 2E diverges, so by the
n In(n)
Comparison Test, the series
diverges.
п In(n)
In(n)
>1, and the series E diverges, so by the Comparison
4. For all n > 2,
Test, the series E
In(n)
diverges.
5. For all n > 2,
and the series > converges, so by the
Comparison Test, the series E
n2-4
n2 4
1
converges.
6. For all n > 2,
n 5
2
and the series 2E
converges, so by the
Comparison Test, the series >
n3 5
converges.

Test each of the following series for convergence by either the Comparison Test or the
Limit Comparison Test. If at least one test can be applied to the series, enter CONV if it
converges or DIV if it diverges. If neither test can be applied to the series, enter NA. (Note: this
means that even if you know a given series converges by some other test, but the comparison
tests cannot be applied to it, then you must enter NA rather than CONV.)
cos(n) /n
NA
Зп + 6
* cos (n) /n
2.
CONV
n3
00 8n°
n* + 3/n
CONV
3.
8n8 – n3 +4
00
3n3
DIV
4.
nº + 6
00
3n3
CONV
5.
n4 + 6
n=1

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