Cosider the above given relational database model of Ticket Booking Application to develop an SQL query to print schedule_id, source, destination and travel_time which having the maximum travel time and sort it in the order of schedule id.
Cosider the above given relational database model of Ticket Booking Application to develop an SQL query to print schedule_id, source, destination and travel_time which having the maximum travel time and sort it in the order of schedule id.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
DBS-145.
![DBS-14.5:
TICKETS
USER_ID
NO_SEATS
TICKET ID
PSCHEDULE_ID varchar2(3)
TRAVEL_DATE
SOURCE
DESTINATION
OBUS NO
SCHEDULE
DURATION
TICKET_ID varchar2(3) SCHEDULE ID
OSCHEDULE ID varchar2(3)
FARE
number(11) #
number(11)
number(11) #
date d
varchar2(20) t
varchar2(20) t
number(11)
number(11) #
USER ID
CANCELLATION
CANCELLATION_ID varchar2(3) t
TICKET_ID
OBD_ID
varchar2(3) BD ID
number(11)
BUS NO
TICKET ID
BD_ID
USERS
PAYMENTS
PAYMENT_ID varchar2(3) t
TICKET_ID varchar2(3)
OBD_ID
DISCOUNT_ID varchar2(3)
USER ID
NAME
number(11)
varchar2(20) t
ADDRESS varchar2(100) t
PHNO
number(11) #
EMAILID varchar2(30) t
BUSES
BUS_NO
number(11)
BUS_NAME varchar2(20) t
TYPE
varchar2(20) t
TOTAL SEATS number (11) #
AVAIL SEATS number(11) #
number(11) DISCOUNT_ID
BOOKINGDETAILS
BD_ID number(11)
ACC_NO number(11) #
NAME varchar2(10) t USER ID
OUSER_ID number(11)
DISCOUNTS
DISCOUNT_ID varchar2(3)
DISCOUNT AMOUNT number(11) a
primary key-not null
foreign key
data type-number
#
d data type-date
it
data type-varchar2
Cosider the above given relational database model of Ticket Booking Application to develop
an SQL query to print schedule_id, source, destination and travel_time which having the
maximum travel time and sort it in the order of schedule id.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e75b372-484c-4491-83bd-63cff6cd1875%2F09c72858-f093-4067-af7b-78e9c2a9c6d0%2Fvfmm6ok_processed.png&w=3840&q=75)
Transcribed Image Text:DBS-14.5:
TICKETS
USER_ID
NO_SEATS
TICKET ID
PSCHEDULE_ID varchar2(3)
TRAVEL_DATE
SOURCE
DESTINATION
OBUS NO
SCHEDULE
DURATION
TICKET_ID varchar2(3) SCHEDULE ID
OSCHEDULE ID varchar2(3)
FARE
number(11) #
number(11)
number(11) #
date d
varchar2(20) t
varchar2(20) t
number(11)
number(11) #
USER ID
CANCELLATION
CANCELLATION_ID varchar2(3) t
TICKET_ID
OBD_ID
varchar2(3) BD ID
number(11)
BUS NO
TICKET ID
BD_ID
USERS
PAYMENTS
PAYMENT_ID varchar2(3) t
TICKET_ID varchar2(3)
OBD_ID
DISCOUNT_ID varchar2(3)
USER ID
NAME
number(11)
varchar2(20) t
ADDRESS varchar2(100) t
PHNO
number(11) #
EMAILID varchar2(30) t
BUSES
BUS_NO
number(11)
BUS_NAME varchar2(20) t
TYPE
varchar2(20) t
TOTAL SEATS number (11) #
AVAIL SEATS number(11) #
number(11) DISCOUNT_ID
BOOKINGDETAILS
BD_ID number(11)
ACC_NO number(11) #
NAME varchar2(10) t USER ID
OUSER_ID number(11)
DISCOUNTS
DISCOUNT_ID varchar2(3)
DISCOUNT AMOUNT number(11) a
primary key-not null
foreign key
data type-number
#
d data type-date
it
data type-varchar2
Cosider the above given relational database model of Ticket Booking Application to develop
an SQL query to print schedule_id, source, destination and travel_time which having the
maximum travel time and sort it in the order of schedule id.
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