cos(2) = - 1 V2 b. sin(x) - 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How would I solve both of these equations for x where x E [0,2pie]

cos(2) = -
1
V2
b. sin(x)
-
2
Transcribed Image Text:cos(2) = - 1 V2 b. sin(x) - 2
Expert Solution
Step 1

topic - Inverse trigonometric functions

cos x is negative in 2 nd and 3 rd quadrant.

sin x is negative in 3rd and 4th quadrant

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