(cos 20+ jsin 20) (cos 60+ jsin 60)1" (cos 30+ jsin 30)°(cjs 1000)

Q: True or false: cos(2pie/3 + pie/6) = cos2pie/3 + cospie/6

A:

Q: 06 Express cos 0 in terms of multiple angles. O (cos50 + cos30 + cos0)/16 O (cos50 + cos30 + cos0)/8…

A: Please find attachment for the details solution

Q: Find   cos(u2)cos(u2)   if   secu=9.545

A:

Q: (1+cosX)(cscX-cot)=

A: See attached file for a step by step explanation.

Q: Cosx 1+sinx 11. 1+sinx 2secx Cosx

A:

Q: -10: Simplify. 9. (1– cosx)(cscx + cotx)

A: Simplify  (1-cosx)(cosecx+cotx)

Q: How does -cos(3t)sec(3t) equal -1?

A: given  -cos(3t)sec(3t) = -1

Q: Eng v-2 Sm (8-号)Cos (o-等) Ci: stetch

A:

Q: sin- a. b. undefined cos(-210) C. Cus270 tan450 d.

A: sin17π6=cosπ2-17π6=cos-7π3=cos7π3=cosπ3=12        cos-210∘ =cos210∘ =-32

Q: (1+Sin O+COs02=a(+Sin0)+cose)

A:

Q: How does sin 15 ° = ((√2-(√3))/2

A:

Q: What is the second step to verifying the identity of the equation? 1+sec²0 = 1 + cos²0 sec²0 sec² 0…

A:

Q: 18( cos54 + isin54°) 3(cos102" + isin102" )

A:

Q: Solve: dr = b (cos 0 dr + r sin 6 de)

A:

Q: cos C25+) Se sincas+) dt

A:

Q: how 300/sin(120+Θ) become 300/cos(30+Θ)?

A: Topic:- trigonometry

Q: Suppose that L = 27, a2 = 1, and the initial temperature distribution is f(x) = 27 - x for 0 <x< 27.…

A:

Q: Calculate tg/tan of 32 knowing that cos64= 0,44.

A: Given that

Q: 2(csc270°)+7(cos90°)^2+sec0°=

A: Solving by trigonometric ratios we have

Q: By equating the real parts of cos5θ + j sin5θ = (cosθ + j sinθ)5 Show that cos5θ = 16cos5θ -…

A: Given By equating the real parts of cos5θ + j sin5θ = (cosθ + j sinθ)5

Q: ( co*2)° + (sinz)* = x). COs x a concrete number ).

A: As this is the Standard Definition of Trigonometric Identities, that,

Q: is it right to say cos (60o-30o) = cos60o .cos 30o+ sin60o.sin30o?

A: cos(A-B)=cosA.cosB+sinA.sinB

Q: Cos2(60°)+sec2(150°)-csc2(210°)

A: To find: