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Corrosion of iron in water is given by, Fe° + 2H + Fe+2 + H2(g) Calculate equilibrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe*] = 10-³ M. O Keq = 7.49x10^14; PH2 = 0.00749 atm %3D %3D Keq = 3.64x10^13; PH2 = 0.0036 atm %3D %3D Keq = 7.69×10^12; PH2 = 0.0065 atm %3D %3D Keq = 2.49x10^14; %3D PH2 = 0.0749 atm %3D Next

Corrosion of iron in water is given by, Fe° + 2H + Fe+2 + H2(g) Calculate equilibrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe*] = 10-³ M. O Keq = 7.49x10^14; PH2 = 0.00749 atm %3D %3D Keq = 3.64x10^13; PH2 = 0.0036 atm %3D %3D Keq = 7.69×10^12; PH2 = 0.0065 atm %3D %3D Keq = 2.49x10^14; %3D PH2 = 0.0749 atm %3D Next

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Corrosion of iron in water is given by, Fe°+ 2H + + Fe+2 + H2 (g) Calculate equilhbrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe] = 10-3 M. %3D Keq = 7.49x10^14; %3D PH2 = 0.00749 atm %3D Keq = 3.64x10^13; PH2 =0.0036 atm %3D O Keq = 7.69x10^123; %3D PH2 = 0.0065 atm Keq = 2.49×10^14; PH2 = 0.0749 atm Next II
Transcribed Image Text:Corrosion of iron in water is given by, Fe°+ 2H + + Fe+2 + H2 (g) Calculate equilhbrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe] = 10-3 M. %3D Keq = 7.49x10^14; %3D PH2 = 0.00749 atm %3D Keq = 3.64x10^13; PH2 =0.0036 atm %3D O Keq = 7.69x10^123; %3D PH2 = 0.0065 atm Keq = 2.49×10^14; PH2 = 0.0749 atm Next II
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