Corrosion of iron in water is given by, Fe° + 2H + Fe+2 + H2(g) Calculate equilibrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe*] = 10-³ M. O Keq = 7.49x10^14; PH2 = 0.00749 atm %3D %3D Keq = 3.64x10^13; PH2 = 0.0036 atm %3D %3D Keq = 7.69×10^12; PH2 = 0.0065 atm %3D %3D Keq = 2.49x10^14; %3D PH2 = 0.0749 atm %3D Next
Corrosion of iron in water is given by, Fe° + 2H + Fe+2 + H2(g) Calculate equilibrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe*] = 10-³ M. O Keq = 7.49x10^14; PH2 = 0.00749 atm %3D %3D Keq = 3.64x10^13; PH2 = 0.0036 atm %3D %3D Keq = 7.69×10^12; PH2 = 0.0065 atm %3D %3D Keq = 2.49x10^14; %3D PH2 = 0.0749 atm %3D Next
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Corrosion of iron in water is given by,
Fe°+ 2H
+ + Fe+2 + H2 (g)
Calculate equilhbrium constant at 298 K.
Calculate pH2 when pH = 10 and [Fe] = 10-3 M.
%3D
Keq =
7.49x10^14;
%3D
PH2 = 0.00749 atm
%3D
Keq = 3.64x10^13;
PH2 =0.0036 atm
%3D
O Keq =
7.69x10^123;
%3D
PH2 = 0.0065 atm
Keq = 2.49×10^14;
PH2 = 0.0749 atm
Next
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf081d72-3f85-49a8-aed0-3abb2bd3850d%2Fa61ddf6e-1612-4f23-af02-2d83365229ba%2Fc4z57v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Corrosion of iron in water is given by,
Fe°+ 2H
+ + Fe+2 + H2 (g)
Calculate equilhbrium constant at 298 K.
Calculate pH2 when pH = 10 and [Fe] = 10-3 M.
%3D
Keq =
7.49x10^14;
%3D
PH2 = 0.00749 atm
%3D
Keq = 3.64x10^13;
PH2 =0.0036 atm
%3D
O Keq =
7.69x10^123;
%3D
PH2 = 0.0065 atm
Keq = 2.49×10^14;
PH2 = 0.0749 atm
Next
II
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