Corrosion of iron in water is given by, Fe° + 2H + Fe+2 + H2(g) Calculate equilibrium constant at 298 K. Calculate pH2 when pH = 10 and [Fe*] = 10-³ M. O Keq = 7.49x10^14; PH2 = 0.00749 atm %3D %3D Keq = 3.64x10^13; PH2 = 0.0036 atm %3D %3D Keq = 7.69×10^12; PH2 = 0.0065 atm %3D %3D Keq = 2.49x10^14; %3D PH2 = 0.0749 atm %3D Next

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