Correct. Solve the given initial value problem. ○x6y² - xy³ = 12 | x³y² − y³ = −4 x³y² + xy³ = -4 xºy² + xy³ = −4 ○xºy² + y³ = −4 dx || 6x³y + y² 2x6 + 3xy y(1) = -2

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