Correct Answer You Answered What is the charge on the complex ion in Ca₂[Fe(CN)6]? 4- 3- 2+ 2-

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Will you explain why the total charge of this complex become -4? Do we not count the charge of Ca? and how do I know what charge Fe is since Fe charge can vary.... 

**Question:** What is the charge on the complex ion in \( \text{Ca}_2[\text{Fe}(\text{CN})_6]? \)

**Choices:**
1. \(\text{4-}\)
2. \(\text{3-}\)
3. \(\text{2+}\)
4. \(\text{2-}\)

**Correct Answer:** The correct answer is not explicitly indicated in the image provided.

**What was Answered:** You answered \(\text{2+}\), as indicated by the red box around the option.

---

**Explanation of Charge Calculation:**

1. The chemical formula provided is \( \text{Ca}_2[\text{Fe}(\text{CN})_6] \).

2. Calcium (Ca) typically has a charge of \(\text{Ca}^{2+}\).

3. Two calcium ions (\( 2 \times \text{Ca}^{2+} \)) contribute a total of \( 2 \times 2+ = 4+ \).

4. The complex ion \( [\text{Fe}(\text{CN})_6] \) should balance this charge because the compound is neutral overall.

5. If we denote the charge on the complex ion \( [\text{Fe}(\text{CN})_6] \) as \( x \):

   \[
   2(2+) + x = 0 \implies 4+ + x = 0 \implies x = -4
   \]

6. Therefore, the charge on the complex ion in \( \text{Ca}_2[\text{Fe}(\text{CN})_6] \) is \(\text{4-}\).

Hence, the correct answer should be \(\text{4-}\).
Transcribed Image Text:**Question:** What is the charge on the complex ion in \( \text{Ca}_2[\text{Fe}(\text{CN})_6]? \) **Choices:** 1. \(\text{4-}\) 2. \(\text{3-}\) 3. \(\text{2+}\) 4. \(\text{2-}\) **Correct Answer:** The correct answer is not explicitly indicated in the image provided. **What was Answered:** You answered \(\text{2+}\), as indicated by the red box around the option. --- **Explanation of Charge Calculation:** 1. The chemical formula provided is \( \text{Ca}_2[\text{Fe}(\text{CN})_6] \). 2. Calcium (Ca) typically has a charge of \(\text{Ca}^{2+}\). 3. Two calcium ions (\( 2 \times \text{Ca}^{2+} \)) contribute a total of \( 2 \times 2+ = 4+ \). 4. The complex ion \( [\text{Fe}(\text{CN})_6] \) should balance this charge because the compound is neutral overall. 5. If we denote the charge on the complex ion \( [\text{Fe}(\text{CN})_6] \) as \( x \): \[ 2(2+) + x = 0 \implies 4+ + x = 0 \implies x = -4 \] 6. Therefore, the charge on the complex ion in \( \text{Ca}_2[\text{Fe}(\text{CN})_6] \) is \(\text{4-}\). Hence, the correct answer should be \(\text{4-}\).
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