******* cording to a survey in a country, 38% of adults do not own a credit card. Suppose a simple random sample of 500 adults is obtained. Complete parts (a) through (d) below Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. A. Approximately normal because n ≤0.05N and np(1-p) < 10 B. Not normal because n≤0.05N and np(1-p) < 10 C. Approximately normal because n ≤0.05N and np(1-p) ²10 D. Not normal because n≤0.05N and np(1-p) 210 ermine the mean of the sampling distribution of p. = 38 (Round to two decimal places as needed.) ermine the standard deviation of the sampling distribution of p 022 (Round to three decimal places as needed.) What is the probability that in a random sample of 500 adults, more than 42% do not own a credit card? probability is 0344 und to four decimal places as needed.) pret this probability. 0 different random samples of 500 adults were obtained, one would expect to result in more than 42% not owning a credit card. nd to the nearest integer as needed.) h

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Question

Solve for B

According to a survey in a country, 38% of adults do not own a credit card. Suppose a simple random sample of 500 adults is obtained. Complete parts (a) through (d) below.
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.
A. Approximately normal because n ≤0.05N and np(1-p) < 10
B. Not normal because n ≤0.05N and np(1-p) < 10
C. Approximately normal because n ≤0.05N and np(1-p) ≥ 10
D. Not normal because n ≤0.05N and np(1-p) ² 10
Determine the mean of the sampling distribution of p.
HA38 (Round to two decimal places as needed.)
Р
Determine the standard deviation of the sampling distribution of p.
0.022 (Round to three decimal places as needed.)
P
(b) What is the probability that in a random sample of 500 adults, more than 42% do not own a credit card?
The probability is 0344
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 500 adults were obtained, one would expect
(Round to the nearest integer as needed.)
h
to result in more than 42% not owning a credit card.
Transcribed Image Text:According to a survey in a country, 38% of adults do not own a credit card. Suppose a simple random sample of 500 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. A. Approximately normal because n ≤0.05N and np(1-p) < 10 B. Not normal because n ≤0.05N and np(1-p) < 10 C. Approximately normal because n ≤0.05N and np(1-p) ≥ 10 D. Not normal because n ≤0.05N and np(1-p) ² 10 Determine the mean of the sampling distribution of p. HA38 (Round to two decimal places as needed.) Р Determine the standard deviation of the sampling distribution of p. 0.022 (Round to three decimal places as needed.) P (b) What is the probability that in a random sample of 500 adults, more than 42% do not own a credit card? The probability is 0344 (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 500 adults were obtained, one would expect (Round to the nearest integer as needed.) h to result in more than 42% not owning a credit card.
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