Copper (II) cation forms a complex ion with four ammonia molecules per the following balanced chemical equation: Cu2+ (aq) + 4 NH3 (aq) ↔ Cu(NH3)42+ (aq) What will be the equilibrium concentration of free Cu2+ in solution if the initial concentration of Cu2+ in solution is 0.0381 M and the initial concentration of ammonia is 0.844 M?  (Kf = 5.6 x 1011)

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