Copper-64 is used in the form of copper acetate to study brain tumors. It decays by a first-order process and has a half-life of12.8 hours. If you start with 33.0 mg of 64Cu-labeled copper acetate, what mass will remain after 3 days and 16 hours?Note: 1 day = 24 hrEQUATIONS AND CONSTANTSE cell = E°cel – (0.0592/n) log Q @ 25 °CR=8.314 J/mol K- =-nFE°sellF= 9.65 x 10 J/V•mol eAG°rn =-(RT) In KE°cell = (RT/nF) In KFor electrolysis:In (No/N) = kt1A=1 C/st12 0.693/kF= 9.65 x 104 C/mol eO 0.765 mgO 0.375 mg0.0938 mgO 0.281 mgO 0.188 mgDELLF1F3F4F6F7F8F9F10F11@23$4124.68RTYKThe Periodic Tablo of th

Given that,half-life, t1/2 = 12.8 hoursInitial quantity, No = 33 mg Now find Nt at t = 3days + 16hours = 3x24 hours + 16 hours = 88 hours Find k using half-life,t1/2 = 0.693kk = 0.693/12.8 = 0.05414 hour-1 Now find Nt ln (No / Nt) = kt NoNt = ekt 33 mgNt = e0.05414x88 = e4.76432 Nt = 33 mg / 117.2513 = 0.2814 mg ~ 0.281 mg Fourth option is the correct answer.

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Copper-64 is used in the form of copper acetate to study brain tumors. It decays by a first-order process and has a half-life of 12.8 hours. If you start with 33.0 mg of 64Cu-labeled copper acetate, what mass will remain after 3 days and 16 hours?

Copper-64 is used in the form of copper acetate to study brain tumors. It decays by a first-order process and has a half-life of 12.8 hours. If you start with 33.0 mg of 64Cu-labeled copper acetate, what mass will remain after 3 days and 16 hours?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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