### Problem DescriptionA capacitor has circular parallel plates with a radius of 3.00 m and is separated by 4.00 mm. The space between the plates is filled with polycarbonate. The properties of polycarbonate are given as follows:- \( k = 2.8 \)- \( E_{\text{max}} = 3.0 \times 10^7 \, \text{V/m} \)### Task List1. **Find the Permittivity of Polycarbonate:** - Calculate the permittivity of the polycarbonate material used between the plates.2. **Determine the Maximum Permissible Voltage:** - Find the maximum voltage that can be applied across the capacitor to avoid dielectric breakdown.3. **Assess Surface Charge Densities:** - When the voltage is equal to the value found in part (2): - Calculate the surface charge density on each plate (\( \sigma \)). - Calculate the induced surface charge density on the surface of the dielectric (\( \sigma_i \)). - Determine the net surface charge density (\( \sigma_{\text{net}} \)).

Answered: Image /qna-images/answer/dc19b009-c979-46e2-b09c-7e862c76c3fe.jpg

Answered: copacitor has aircular parallel plaks…

Similar questions

Thank you in advance!! A design specifications is the be produce and you are asked to provide information about how a capacitor might be produced. The capacitor must operate under a potential difference of 240 Volts. It must have a Capacitance value of 12 μF . It's plates (square) should each have a side of 2m. (a) What value of plate seperation would be needed with the specifacations aboves(meters) , (b) and if the capacitor 12 μF is to be connected to the 240 V source than how much charge would apear on each plates? (Coulombus)
The potential distribution in a dielectric material (& = 8) is V = 4x³yz² V. Find V, E, and P at point (2, –5, 3).
The uniform electric field E in the air outside the plane boundary of an LIH dielectric material is at an angle of 30° to the normal to the The relative permittivity & of the dielectric is 3.0. Find the angle that the electric field in the dielectric makes with the normal. Clearly state any boundary conditions that you boundary, as shown in Figure 2. use. 30° Eair air dielectric € = 3.0
Three copocitocs ore connected as shown in the figure. Ihe Capacitors all have +he some dielectric material and The above Copacitonce Values include the dielectric effect, 2UF a CE a What is the equivalent copacitonce between a ond 6? 6, If there is a voltoge of 1ov between a ond b. what is the charge on the 2 UF capacitor? C. For case (b), what is the Voltage across the 4uF Capacitor? d. Suppose now we take the 4e F copacitor from where it is ond put all three capacitors in series. Because of the dielectrics used, each copacitor will break down if the potentia) exceeds 60 V. What is the maxinum Voltage that Can be applied across a ond b in this case without breaking down ony of the Capacitors?
A dielectric- filled por allel-plate capacitor as pleite area A=10.0cm²,plate separation d= 8.00 mm an K = 4•00. The capacitor is connected to a battery oltage V= 5•00 V Throughout nd dieleitric tonštad that creates a the problem, use constant ve -12 U, of the dielect erically in joules d मास्पु Find the ric - filled copacitor energy つ) मा र #he txpress your an Swer nu 2 The dielectric plaite i's now slewly pulled eut of the capacater, which rencains connected to the battery. tind the energy Uz ator at the moment when the Lapecitor is capa half-filled with Hhe dielectric. Express your answers nuimerically in joules 3.The capecitor s Row disconnected from the battery and the dielectric plate is slowly removed the rest ef Hhe way out ef the capacitor. find the new enerqy ef he capecitor Ug Express your answers ruemerically ie joules 4.J0the the dielectric from the disconnected work Wis done by e exter nal ager frocess of removing The remaining pertion ef the capacitor, how much nt ating…
A charge ±Q is placed on the plates of a capacitor, which is then disconnected from the outside world. The separation between the plates is changed, and it is found that the voltage across the plates decreases. (a) Have the plates been moved closer together or farther apart? O closer together O farther apart (b) If the new voltage is smaller than the original voltage by a factor of six, what is the ratio of the new plate spacing to the original spacing?
If you have a capacitor that stores 2.5 J of energy with an aur gap and power supply at 10 kV, find the energy stored with a dielectric (Er = 8.5) is placed between the plates with the gap between them is decreased by 15% and the voltage goes up to 20 kV.
A parallel-plate capacitor with plate separation d is connected to a battery that has potential difference AVbat. Without breaking any of the connections, insulating handles are used to increase the plate separation to 2d.
For the system of in Fig. a potential difference 7.5 nF capacitors shown of 25 V is maintained across 18.0 nF 30.0 nF 10.0 nF ab. (a) What is the equivalent HHHH capacitance of this system between a and b? 6.5 nF
Please help
A capacitor with capacitance (C) = 4.50 microFarad is connected to a 12.0 V battery. What is the magnitude ofthe charrge on each of the plates?
A capacitor is composed of 2 plates separated by a sheet öf insulatih and of relative permittivity 4. The distance between the plates is increased to allow the insertion of a second sheet of 5mm thick and of relative permittivity &,. If the equivalent capacitance is one third of the original capacitance, find the value of ɛ,.

SEE MORE QUESTIONS