cOOEt1. EtO Na*NaOH, H20HCI, H2Ocompound acompound bcompound c (C3H1002)2. HCI, H2OHeatHeat`COOEtClaisen condensation between a diethyl ester and an ethyl ester followed by saponification, acidification, and decarboxylation forms a diketone.Work out this synthesis on a separate sheet of paper, and then draw the structure of compound a.• You do not have to consider stereochemistry.• You do not have to explicitly draw H atoms.Do not include lone pairs in your answer. They will not be considered in the grading.• Do not include counter-ions, e.g., Na", I", in your answer.

In Claisen condensation reaction, esters containing alpha hydrogens react with strong base and form…

COOET 1. EtO Na* NaOH, H2O HCI, H20 > compound a compound b compound c (C3H1002) 2. HCI, H2O Heat Heat `COOET Claisen condensation between a diethyl ester and an ethyl ester followed by saponification, acidification, and decarboxylation forms a diketone.

COOET 1. EtO Na* NaOH, H2O HCI, H20 > compound a compound b compound c (C3H1002) 2. HCI, H2O Heat Heat `COOET Claisen condensation between a diethyl ester and an ethyl ester followed by saponification, acidification, and decarboxylation forms a diketone.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

cOOEt
1. EtO Na*
NaOH, H20
HCI, H2O
compound a
compound b
compound c (C3H1002)
2. HCI, H2O
Heat
Heat
`COOEt
Claisen condensation between a diethyl ester and an ethyl ester followed by saponification, acidification, and decarboxylation forms a diketone.
Work out this synthesis on a separate sheet of paper, and then draw the structure of compound a.
• You do not have to consider stereochemistry.
• You do not have to explicitly draw H atoms.
Do not include lone pairs in your answer. They will not be considered in the grading.
• Do not include counter-ions, e.g., Na", I", in your answer.

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Alkenes can be converted to alcohols by reaction with mercuric acetate to form a β-hydroxyalkylmercury(II) acetate compound, a reaction called oxymercuration. Subsequent reduction with NaBH4 reduces the C–Hg bond to a C–H bond, forming the alkyl alcohol, a reaction called demercuration. Draw the structures of the Hg-containing compound(s) and the final alcohol product(s) formed in the following reaction sequence, omitting byproducts. If applicable, draw hydrogen at a chirality center and indicate stereochemistry via wedge-and-dash bonds.