Use C++ **Converting Decimal into Binary: An Iterative Function Approach**This tutorial covers how to transform a decimal number into its binary equivalent using an iterative function.### Steps to Convert Decimal 20 to Binary:1. **Divide the Number:** - Divide the decimal number by 2. - Record the quotient and remainder. - Repeat the process with the quotient until it equals zero.2. **Illustration:** - 20 divided by 2 gives a quotient of 10 and a remainder of 0. - 10 divided by 2 gives a quotient of 5 and a remainder of 0. - 5 divided by 2 gives a quotient of 2 and a remainder of 1. - 2 divided by 2 gives a quotient of 1 and a remainder of 0. - 1 divided by 2 gives a quotient of 0 and a remainder of 1.3. **Binary Conversion:** - Collect the remainders starting from the last to the first. - Result: 10100 - Hence, 20 in decimal is equal to 10100 in binary.### Other Examples:- **Decimal 10** converts to **Binary 1010**- **Decimal 33** converts to **Binary 100001**- **Decimal 150** converts to **Binary 10010110**- **Decimal 55** converts to **Binary 110111**This method ensures an efficient approach to converting integers into their binary form, enhancing comprehension of binary systems in computing.

The above question is solved in step 2 :- Solution :- C++ code:- #include <bits/stdc++.h> #include <string.h> using namespace std; int main() { int y = 1; while(y !=0) { int val,answer[64]; string inp; cout<<"Enter one positive integer : "; cin>>val; int j = 0; int cnt = val; while (val > 0) { answer[j] = val % 2; val = val / 2; j++; } cout<<"Decimal "<<cnt<<" -> Binary "; for (int k=j-1;k>=0; k--) { cout << answer[k]; } cout<<endl; cout<<"More (y/n) ? "; cin>>inp; if(inp == "n") { y = 0; } cout<<"\n"; } return 0; } Screenshot of code and output :-