Convert the rectangular equation to polar form. xy = 14

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
**Convert the rectangular equation to polar form.**

\[ xy = 14 \]

**Solution:**

In rectangular coordinates:
- \( x \) is the horizontal coordinate.
- \( y \) is the vertical coordinate.

In polar coordinates:
- \( r \) is the distance from the origin.
- \( \theta \) is the angle measured counterclockwise from the positive \( x \)-axis.

Using the relationships between rectangular and polar coordinates:
\[ x = r \cos(\theta) \]
\[ y = r \sin(\theta) \]

Substitute these into the given equation:
\[ (r \cos(\theta))(r \sin(\theta)) = 14 \]

This simplifies to:
\[ r^2 \cos(\theta) \sin(\theta) = 14 \]

Hence, the polar form of the given rectangular equation is:
\[ r^2 \cos(\theta) \sin(\theta) = 14 \]

**Graph/Diagram Description:** 

There is no graph or diagram associated with this problem. There is a text box below the equation where the polar form solution would be entered.
Transcribed Image Text:**Convert the rectangular equation to polar form.** \[ xy = 14 \] **Solution:** In rectangular coordinates: - \( x \) is the horizontal coordinate. - \( y \) is the vertical coordinate. In polar coordinates: - \( r \) is the distance from the origin. - \( \theta \) is the angle measured counterclockwise from the positive \( x \)-axis. Using the relationships between rectangular and polar coordinates: \[ x = r \cos(\theta) \] \[ y = r \sin(\theta) \] Substitute these into the given equation: \[ (r \cos(\theta))(r \sin(\theta)) = 14 \] This simplifies to: \[ r^2 \cos(\theta) \sin(\theta) = 14 \] Hence, the polar form of the given rectangular equation is: \[ r^2 \cos(\theta) \sin(\theta) = 14 \] **Graph/Diagram Description:** There is no graph or diagram associated with this problem. There is a text box below the equation where the polar form solution would be entered.
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