Convert the point with cylindrical coordinates 11π 13, 5 to Cartesian coordinates. Enter your answer 9 6 as an ordered triple using exact values involving radicals as necessary. (x, y, z)

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Chapter1: Functions And Models
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**Converting Cylindrical to Cartesian Coordinates**

**Problem:**

Convert the point with cylindrical coordinates \((13, \frac{11\pi}{6}, 5)\) to Cartesian coordinates. Enter your answer as an ordered triple using exact values involving radicals as necessary.

\((x, y, z) = \) [Blank Box for Answer]

**Explanation:**

To convert from cylindrical coordinates \((r, \theta, z)\) to Cartesian coordinates \((x, y, z)\), use the following formulas:

1. \(x = r \cdot \cos(\theta)\)
2. \(y = r \cdot \sin(\theta)\)
3. \(z = z\)

Given:
- \(r = 13\)
- \(\theta = \frac{11\pi}{6}\)
- \(z = 5\)

Plug these values into the formulas to find the Cartesian coordinates.
Transcribed Image Text:**Converting Cylindrical to Cartesian Coordinates** **Problem:** Convert the point with cylindrical coordinates \((13, \frac{11\pi}{6}, 5)\) to Cartesian coordinates. Enter your answer as an ordered triple using exact values involving radicals as necessary. \((x, y, z) = \) [Blank Box for Answer] **Explanation:** To convert from cylindrical coordinates \((r, \theta, z)\) to Cartesian coordinates \((x, y, z)\), use the following formulas: 1. \(x = r \cdot \cos(\theta)\) 2. \(y = r \cdot \sin(\theta)\) 3. \(z = z\) Given: - \(r = 13\) - \(\theta = \frac{11\pi}{6}\) - \(z = 5\) Plug these values into the formulas to find the Cartesian coordinates.
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