Convert the given system to an augmented matrix. 2x, = -10 + X3 = -4x, + 2x2 -1 3x, - X2 + X3 = 4 -4 2 -2 10 1 1 3 -1 1 -4 2 -2 -10 1 1 1 -1 3 -1 4 2 -2 0 1 3 -1 -4 -10 -1 4. -4 2 -2 -10 1 0 3 -1 -1 1 4 -4 2 -2 10 1 1 3 -1 4. Find all solutions by transforming the system to reduced echelon form and back substituting. (If there are an infinite number of solutions use s, as your parameter. If there is no solution, enter NO SOLUTION.)
Convert the given system to an augmented matrix. 2x, = -10 + X3 = -4x, + 2x2 -1 3x, - X2 + X3 = 4 -4 2 -2 10 1 1 3 -1 1 -4 2 -2 -10 1 1 1 -1 3 -1 4 2 -2 0 1 3 -1 -4 -10 -1 4. -4 2 -2 -10 1 0 3 -1 -1 1 4 -4 2 -2 10 1 1 3 -1 4. Find all solutions by transforming the system to reduced echelon form and back substituting. (If there are an infinite number of solutions use s, as your parameter. If there is no solution, enter NO SOLUTION.)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.CT: Chapter Test
Problem 9CT
Related questions
Question
![Convert the given system to an augmented matrix.
-4x, + 2x2
2x3 = -10
X1
X3 =
-1
3x1
X.
x3
-4
2 -2
10
1
1
1
3 -1
1
4
-4
2 -2
-10
1 -1
3 -1
1
1
4
-4
2
-2
-10
1
-1
3 -1
1
-4
2 -2
-10
1
1
-1
3 -1
1
-4
2
-2
10
1
1
1
3 -1
1
Find all solutions by transforming the system to reduced echelon form and back substituting. (If there are an infinite number of solutions use s, as your parameter. If there is no solution, enter NO SOLUTION.)
(x1, X2, X3) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6412df56-77f5-4860-8425-a3a3fd6e5565%2F9acef3df-7690-445a-b3da-edee0640dbac%2F39gv85_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Convert the given system to an augmented matrix.
-4x, + 2x2
2x3 = -10
X1
X3 =
-1
3x1
X.
x3
-4
2 -2
10
1
1
1
3 -1
1
4
-4
2 -2
-10
1 -1
3 -1
1
1
4
-4
2
-2
-10
1
-1
3 -1
1
-4
2 -2
-10
1
1
-1
3 -1
1
-4
2
-2
10
1
1
1
3 -1
1
Find all solutions by transforming the system to reduced echelon form and back substituting. (If there are an infinite number of solutions use s, as your parameter. If there is no solution, enter NO SOLUTION.)
(x1, X2, X3) =
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