Convert the following PDA to CFG: ({g, p}. {0, 1}, {Zo, X},&, q, Zo, {p}) P = 1. d(q,0, Zn) = {(q, X Za)}. 2. 64.0, X) — {(ч, XX)). 3. 8(4,1, X) = {(q, X)}. 4. 8(g, €, X) = {(p, e)}. 5. 8(p, e, X) = {(p,e)}. 6. 6(р, 1, X) %3D {(p, XX)}. 7. 6(р, 1, 20) 3 {(p, e)}.
Convert the following PDA to CFG: ({g, p}. {0, 1}, {Zo, X},&, q, Zo, {p}) P = 1. d(q,0, Zn) = {(q, X Za)}. 2. 64.0, X) — {(ч, XX)). 3. 8(4,1, X) = {(q, X)}. 4. 8(g, €, X) = {(p, e)}. 5. 8(p, e, X) = {(p,e)}. 6. 6(р, 1, X) %3D {(p, XX)}. 7. 6(р, 1, 20) 3 {(p, e)}.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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
Transcribed Image Text:Convert the following PDA to CFG:
({g, p}. {0, 1}, {Zo, X},&, q, Zo, {p})
P =
1. d(q,0, Zn) = {(q, X Za)}.
2. 64.0, X) — {(ч, XX)).
3. 8(4,1, X) = {(q, X)}.
4. 8(g, €, X) = {(p, e)}.
5. 8(p, e, X) = {(p,e)}.
6. 6(р, 1, X) %3D {(p, XX)}.
7. 6(р, 1, 20) 3 {(p, e)}.
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