Convert the following equation to standard form by completing the square. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola on separate paper or graph paper (NOT on Desmos). You will need to mark enough points to show the proper stretch of the graph. y? – 2y + 12x – 35 = 0 1. What is the equation in standard form? 2. What is the vertex? 3. *Where is the focus located? 4. *What is the directrix? (Type an equation) 5. *Graph the parabola (labeling the vertex, focus and endpoints of the latus rectum) Submit this graph in your work

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A: Solution is here

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A: We know that the standard equation of parabola is  (y-beta)^2=4a(x-alpha)

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Q: 5. Graph the parabola y -2x² + 12x 11. Indicate the vertex and the intercepts. ==

A: We can solve it by general form of parabola as follows

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Q: Determine another point on each parabola. The axis of symmetry is x = 3. A point on the parabola is…

A: The axis of symmetry of a parabola is a line about which the parabola is symmetrical.

Q: 3/4 no Problem 6. Is {[a], [b], [c], [d], [a, b], [b, c], [c, d], [a, d], [a, c], [b, d], [a, c, d]}…

A: Ans-6Yes, the set {[a], [b], [c], [d], [a, b], [b, c], [c, d], [a, d], [a, c], [b, l],[a, c, d]}…

Q: Q1) Find an equation of the following parabola and sketch it where Vertex: (3,2) and Focus:(1,2)

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Q: Find the equation of the parabola

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Q: -6 -2₂ 2- --2-

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Q: Graph t. pulabola. x=-2(y-6)²-1 12 10 X图

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Q: Determine the focus, directrix, axis, and direction of the parabola. Then use this information to…

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Q: Find the vertex, focus, and directrix of the following parabola. Graph the equation. Verify your…

A: Parabola

Q: Parabola.  The vertex is ( 4 , 7 ) and the equation for the directrix is y = 12.

A: