Convert the following BNF grammar to EBNF: < loop > := while < condition > < stmt_list > < condition > := < | > | == | != < stmt_list > := < stmt > | < stmt >; < stmt_list > < stmt > := = := + | - | := a | b | ... | z | A | B | ... | Z Convert the following EBNF to BNF: := ( < exp > . ) | ( < exp_list >) | < symbol > < symbol > := < alphabets > { < alphabets > | < numeric > } < exp_list > := { < exp >} < alphabets > := a | b | ... | z < numerics > := 0 | 1 | ... | 9
Convert the following BNF grammar to EBNF: < loop > := while < condition > < stmt_list > < condition > := < | > | == | != < stmt_list > := < stmt > | < stmt >; < stmt_list > < stmt > := = := + | - | := a | b | ... | z | A | B | ... | Z Convert the following EBNF to BNF: := ( < exp > . ) | ( < exp_list >) | < symbol > < symbol > := < alphabets > { < alphabets > | < numeric > } < exp_list > := { < exp >} < alphabets > := a | b | ... | z < numerics > := 0 | 1 | ... | 9
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Convert the following BNF grammar to EBNF:
< loop > := while < condition > < stmt_list >
< condition > := <exp > < <exp > | <exp > > <exp > | <exp > == <exp > | <exp > != <exp >
< stmt_list > := < stmt > | < stmt >; < stmt_list >
< stmt > := <var > = <exp >
<exp > := <var > + <var > | <var > - <var > | <var >
<var > := a | b | ... | z | A | B | ... | Z
Convert the following EBNF to BNF:
<exp > := ( < exp > . <exp >) | ( < exp_list >) | < symbol >
< symbol > := < alphabets > { < alphabets > | < numeric > }
< exp_list > := { < exp >}
< alphabets > := a | b | ... | z
< numerics > := 0 | 1 | ... | 9
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