Convert the C code below into RISC-V assembly language for the following scenarios: 1) Starting address of array A is x3 2) variable last is assigned to register x12 3) the return value of the procedure is assigned to register x20 Note that it is a non-leaf procedure
Convert the C code below into RISC-V assembly language for the following scenarios: 1) Starting address of array A is x3 2) variable last is assigned to register x12 3) the return value of the procedure is assigned to register x20 Note that it is a non-leaf procedure
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Convert the C code below into RISC-V assembly language for the following scenarios:
1) Starting address of array A is x3
2) variable last is assigned to register x12
3) the return value of the procedure is assigned to register x20
Note that it is a non-leaf procedure
![5:11 1
ll 3G
X Computer Organization Assignm...
C Language Code:
void main ( )
{
int A [10] = { -5, 6, 20, -83, 99, 19, 100, 0, -46, 25};
int Z = order (A, 9);
}
int order (int array_in [ ], int last)
{
int count = 0;
for (int i= 0; i < last; i++)
if (array_in[i] > array_in[i+1])
temp = array_in[i];
array_in[i] = array_in[i+1];
array_in[i+1] = temp;
count++;
}
if (last == 1)
return count;
else
return (count + order (array_in, last – 1));
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F49c0ee1c-03b3-4d0e-aa32-2670a7154c9d%2Fc2f22748-ac65-45a2-9bcd-320ec32b8065%2Fjohd07d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5:11 1
ll 3G
X Computer Organization Assignm...
C Language Code:
void main ( )
{
int A [10] = { -5, 6, 20, -83, 99, 19, 100, 0, -46, 25};
int Z = order (A, 9);
}
int order (int array_in [ ], int last)
{
int count = 0;
for (int i= 0; i < last; i++)
if (array_in[i] > array_in[i+1])
temp = array_in[i];
array_in[i] = array_in[i+1];
array_in[i+1] = temp;
count++;
}
if (last == 1)
return count;
else
return (count + order (array_in, last – 1));
}
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