Convert conductivity to molar concentration by using the initial conductivity of the NaOH solution as a conversion factor. Convert each initial rate into the units: mols/L/s. For example, if the initial conductivity of a 0.005 mol/L NaOH solution was 2000 uS/cm and initial rate was 5.0 uS/cm/s, you would convert the rate to moles/ L /s by completing the following calculations: Rate= 5.0uS/cm/s [(0.005 mol/L)(2000 uS/cm)]= 1.25 x 10^-5 mol/L/s. After calculating using these new values out the rate constant for each trial, what is the average value of k? TrialNaOHCH3COOC2H5Initial Condcutivity of NaOH Solution (uS/cm)Initial Rate (uS/cm)/s)121 ml2.1ml128524.72221 ml2.1ml239950.32321 ml2.1ml126223.72

The formula for converting μs/cm/s into mol/l/s is already mentioned in the question. Firstly,…

Answered: Convert conductivity to molar…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Convert conductivity to molar concentration by using the initial conductivity of the NaOH solution as a conversion factor. Convert each initial rate into the units: mols/L/s. For example, if the initial conductivity of a 0.005 mol/L NaOH solution was 2000 uS/cm and initial rate was 5.0 uS/cm/s, you would convert the rate to moles/ L /s by completing the following calculations: Rate= 5.0uS/cm/s [(0.005 mol/L)(2000 uS/cm)]= 1.25 x 10^-5 mol/L/s.
After calculating using these new values out the rate constant for each trial, what is the average value of k?

Trial	NaOH	CH3COOC2H5	Initial Condcutivity of NaOH Solution (uS/cm)	Initial Rate (uS/cm)/s)
1	21 ml	2.1ml	1285	24.72
2	21 ml	2.1ml	2399	50.32
3	21 ml	2.1ml	1262	23.72

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