Convert between mass, moles, and atoms of an element. How many Kr atoms are there in a 73.1 gram sample of element- atoms

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Convert between Mass, Moles, and Atoms of an Element

**Question:**
How many Kr (Krypton) atoms are there in a 73.1 gram sample of elemental Kr?

**Answer:**
Please enter the number of atoms in the provided box.

**Answer Box:**
____ atoms

#### Explanation:
To solve this question, you would typically follow these steps:

1. **Find the Molar Mass of Krypton**: The molar mass of Krypton (Kr) can be found on the periodic table. It is approximately 83.798 grams per mole.
2. **Convert Grams to Moles**:
   Use the formula: 
   \[ \text{Number of moles} = \frac{\text{Mass (grams)}}{\text{Molar Mass (grams per mole)}} \]
   For Krypton: 
   \[ \text{Number of moles} = \frac{73.1 \text{ grams}}{83.798 \text{ grams/mole}} \]
3. **Convert Moles to Atoms**:
   Use Avogadro's number, which is \( 6.022 \times 10^{23} \text{ atoms/mole} \). 
   \[ \text{Number of atoms} = \text{Number of moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \]

By following these steps, students can determine the number of atoms in a given sample.
Transcribed Image Text:### Convert between Mass, Moles, and Atoms of an Element **Question:** How many Kr (Krypton) atoms are there in a 73.1 gram sample of elemental Kr? **Answer:** Please enter the number of atoms in the provided box. **Answer Box:** ____ atoms #### Explanation: To solve this question, you would typically follow these steps: 1. **Find the Molar Mass of Krypton**: The molar mass of Krypton (Kr) can be found on the periodic table. It is approximately 83.798 grams per mole. 2. **Convert Grams to Moles**: Use the formula: \[ \text{Number of moles} = \frac{\text{Mass (grams)}}{\text{Molar Mass (grams per mole)}} \] For Krypton: \[ \text{Number of moles} = \frac{73.1 \text{ grams}}{83.798 \text{ grams/mole}} \] 3. **Convert Moles to Atoms**: Use Avogadro's number, which is \( 6.022 \times 10^{23} \text{ atoms/mole} \). \[ \text{Number of atoms} = \text{Number of moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \] By following these steps, students can determine the number of atoms in a given sample.
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