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- The specific reaction rate constant k is a strong function of temperature according to the following equation: 1 In the equation above, the reaction rate constant k is expressed in R is the universal gas constant 8.314- What is the unit of A? O mol m OK Om O J O mol K J mol 01 S Pa.m ³ m k=Axexp- Pa.m³ constant (1.314 P-²). mol. K E RT and T is the absolute temperature in K. The equation is dimensionally homogenous.Please answer the question correctly with solution. Please dont use transcribed. Note: the tolerance is ± 1 in the third significant digit. Thank youA) What is an equation to equate KE and GPE? B) A gas is held in a container of 15 m^3 in volume and a pressure of 5 Pa. If the volume isincreased to 26 m^3 what is the pressure of the gas? c)A syringe has a volume of 5 cm^3 and a temperature of 300 k. Upon heating the syringeexpands to a volume is now 5.5cm^3, what is the temperature of the syringe?
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- In the 1930s, the biologist Max Kleiber studied animals' metabolic rates. He 3 4 1 expressed the ratio of the rates for two animals by the relation where "1 %3D m1 and 2 are the animals' metabolic rates and m1 and m2 are the animals' masses. a) Compare the metabolic rates of a 70-kg man and a 15-kg dog. b) Compare the metabolic rates of a 5-kg cat with that of a 50-g mouse. c) Compare the metabolic rates of a 10-g hummingbird and a 5000-kg elephant.Please include solution. Thank you!The tolerance is ±2%. "box your answer"
- 2 (a) How many protons are in 2.00 kg of pure iron? Answer using scientific notation nt)Question 5: An antibody suspension is applied through a tube at a flow rate of 9 lit/min. The mass diffusivity of the antibody in the suspension is 75 um?/s. The tube has an internal diameter of 1.5 cm and a length of 20 cm. 5a. Calculate Sherwood number 5b. Calculate Schmidt number 5c. Calculate the rate of antibody deposition across the internal surface of the tube Antibody solution Density = 1050 kg/m³ Viscosity = 2 mPa.s Concentration = 5 mM Internal diameter = 1.5 cm Length = 20 cmX 1.CO re to search Combustion and Elemental Anal X Edpuzzle Et X Edpuzzle Aktiv Chemistry Question 27 of 35 ▸ Determine the mass in grams of 5.20 x 1021 atoms of carbon. (The mass of one mole of carbon is 12.01 g.)